leetcode--Fraction to Recurring Decimal

Given two integers representing the numerator and denominator of a fraction, return the fraction in string format.

If the fractional part is repeating, enclose the repeating part in parentheses.

For example,

  • Given numerator = 1, denominator = 2, return "0.5".
  • Given numerator = 2, denominator = 1, return "2".
  • Given numerator = 2, denominator = 3, return "0.(6)".
public class Solution {
    public String fractionToDecimal(int numerator, int denominator) {
		if(numerator==0) return "0";
		if(denominator==0) return "";
		String res="";
		if((numerator<0)^(denominator<0)) res+="-";
		long num = numerator;
		long den = denominator;
		num = Math.abs(num);
		den = Math.abs(den);
		long ans = num/den;
		res += ans;
		if(num%den==0) return res;
		else res+=".";
		
		long t = num%den*10;
		System.out.println(den);
		Map<Long,Integer> map = new HashMap<Long,Integer>();
		while(t>0){
			if(map.containsKey(t)){
				int mid = map.get(t);
				String part1 = res.substring(0, mid);  
	            String part2 = res.substring(mid, res.length());  
	            res = part1 + "(" + part2 + ")";  
	            return res;
			}
			map.put(t, res.length());
			ans = t/den;
			System.out.println(ans);
			res += String.valueOf(ans);
			t = (t%den)*10;
		}
		return res;
    }
}

你可能感兴趣的:(leetcode--Fraction to Recurring Decimal)