(leetcode)Evaluate Reverse Polish Notation

Question:

Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are +-*/. Each operand may be an integer or another expression.

Some examples:

  ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
  ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6

代码实现:

class Solution {
public:
int evalRPN(vector<string> &tokens) {
    stack<int> temp;
    int sum = 0;
    int  op1,op2,op3;
    for(int i =0;i < tokens.size();i++)
    {
        if(tokens[i]!= "\0")
        {
            if((tokens[i]=="+"||tokens[i]=="-"||tokens[i]=="*"||tokens[i]=="/")&&temp.size()>=2)
            {
                op2 = temp.top();temp.pop();
                op1 = temp.top();temp.pop();
                op3 = op(op1,op2,tokens[i][0]);
                temp.push(op3);
            }
            else
                temp.push(stoi(tokens[i]));
        }

    }
    return temp.top();
}

int op(int op1,int op2,char op)
{

    switch(op)
    {
        case '+':return op1+op2;

        case '-': return op1-op2;

        case '*': return op1*op2;

        case '/':
        if(op2!=0)
        return op1/op2;
        else
        printf("error!\n");
    }

}
};


已AC。

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