今天试了试Python发邮件,突然想到能不能群发邮件呢?群发邮件是smtplib的一个bug,不过最终还是解决了。
直接上代码了
import smtplib msg = MIMEMultipart() #构造附件1 att1 = MIMEText(open('/home/a2bgeek/develop/python/hello.py', 'rb').read(), 'base64', 'gb2312') att1["Content-Type"] = 'application/octet-stream' att1["Content-Disposition"] = 'attachment; filename="hello.txt"'#这里的filename可以任意写,写什么名字,邮件中显示什么名字 msg.attach(att1) #构造附件2 #att2 = MIMEText(open('/home/a2bgeek/develop/python/mail.py', 'rb').read(), 'base64', 'gb2312') #att2["Content-Type"] = 'application/octet-stream' #att2["Content-Disposition"] = 'attachment; filename="123.txt"' #msg.attach(att2) #加邮件头 strTo = ['[email protected]', '[email protected]', '[email protected]'] msg['to']=','.join(strTo) msg['from'] = '[email protected]' msg['subject'] = '邮件主题' #发送邮件 try: server = smtplib.SMTP() server.connect('smtp.163.com') server.login('[email protected]','yourpasswd') server.sendmail(msg['from'], strTo ,msg.as_string()) server.quit() print '发送成功' except Exception, e: print str(e)
The problem is that SMTP.sendmail and email.MIMEText need two different things.
email.MIMEText sets up the “To:” header for the body of the e-mail. It is ONLY used for displaying a result to the human being at the other end, and like all e-mail headers, must be a single string. (Note that it does not actually have to have anything to do with the people who actually receive the message.)
SMTP.sendmail, on the other hand, sets up the “envelope” of the message for the SMTP protocol. It needs a Python list of strings, each of which has a single address.
So, what you need to do is COMBINE the two replies you received. Set msg‘To’ to a single string, but pass the raw list to sendmail.
好了今天就到这里。
参考资料:
http://www.cnblogs.com/xiaowuyi/archive/2012/03/17/2404015.html
http://sar4.com/python/2012/12/31/smtplib-list-object-has-no-attribute-lstrip/