todo01

http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=2&sectionid=1&problemid=3

为什么非要先化成最简???

#include <iostream>
using namespace std;

long long gcd(long long a, long long b)
{
        long long c = a%b;
        while(c){
                a = b;
                b = c;
                c = a%b;
        }
        return b;
}

int main(int argc, char *argv[])
{
        int t, i;
        char c1, c2;
        long long  a, b, c, d;
        cin>>t;
        for(i=0; i<t; i++){
                cin>>a>>c1>>b>>c>>c2>>d;
                // long long x = gcd(a, b);
                // a /= x;
                // b /=x;
                // long long y = gcd(c, d);
                // c /=y;
                // d /=y;
                a = a*c/gcd(a, c);
                b = gcd(b, d);
                if(a%b)
                        cout<<a/gcd(a, b)<<"/"<<b/gcd(a, b)<<endl;
                else
                        cout<<a/b<<endl;
        }
        return 0;
}


你可能感兴趣的:(c)