Problem 6 自然数求差
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
|
Answer:
|
25164150 |
public class Squares { public static void main(String args[]){ int sum=0; int mul=1; int mulsum=0; for(int i=1;i<=100;i++){ sum+=i; mul=i*i; mulsum+=mul; } System.out.println(sum*sum-mulsum); } }