C++能否抛出一个不是继承自std::exception的异常

有这样一道面试题目：

 

try 
{ 
} 
catch(const std::exception &e) 
{ 
} 
catch(...) 
{ 
  //Is this block needed? 
} 

问第二个catch会捕获到异常吗？

 

答案是是的。。。你可以throw任何类型，不一定是std::exception的子类。可以throw一个整数，或者一个字符串。

http://stackoverflow.com/questions/908092/in-c-is-is-possible-to-throw-an-exception-that-will-not-be-caught-by-stdexce

 

yes. you can throw any type, not necessary types that inherit from std::exception.
you can write throw 1; to throw and int or throw "hello"; to throw a char*, both of which do not inherit from std::exception. this is however considered bad practice because the user of the class can't expect you to throw anything. If you don't want to inherit from std::exception what you usually do is create your own exception hierarchy.