joj2318

  2318: Diamond

Result	TIME Limit	MEMORY Limit	Run Times	AC Times	JUDGE
	3s	16384K	1552	578	Standard

Draw a diamond shape with character '*'.

Input

There are several lines in the input, each line is a integer N(N<100), N is zero means the end of input.

Output

For each line of input, draw a diamond whose width is N like sample. Notice there is no unnecessary spaces after '*' in the same line.

Output a blank line after each case.

Sample Input

3
0

Sample Output

  *
 ***
*****
 ***
  *

 
/*
本人代码：
#include<iostream>
#include<string>
using namespace std;
int main()
{
    int i, n;
 while(cin>>n,n)
 {
  for(i=1;i<n;i++)
  {
    cout<<string((n-i),' ');
       cout<<string(2*i-1,'*')<<endl;
  
  }
  for(i=n;i>=1;i--)
  {
    cout<<string((n-i),' ');
       cout<<string(2*i-1,'*')<<endl;
  
  }
  cout<<endl;
 }
 
 return 0;
}*/
#include<stdio.h>
#include<memory.h>
char s1[201],s2[201];
int main()
{
 int n,i,p,k,temp,x,y;
 memset(s1,' ',sizeof(s1));
 memset(s2,'*',sizeof(s2));
 s1[200]=s2[200]='\0';
 while(scanf("%d",&n),n)
 {
  k=n*2-1;
  for(i=1,p=n-1;i<=k;i++,p--)
  {
   x=p>0?p:-p;
   temp=i<n?n-i:i-n;
   y=(n-temp)*2-1;
   printf("%s",s1+200-x);
   puts(s2+200-y);
  }
  putchar('\n');
 }
 return 0;
}