SQL小计合计并排序

--说明：个人学习笔记，实现小计合计显示，分组按BANK_ID+OP_DATE升序排序
--测试数据
CREATE TABLE #TB(ID VARCHAR(10),BANK_ID VARCHAR(10),OP_DATE VARCHAR(10),OPERATOR_NO VARCHAR(20),AMT DECIMAL(10,2))
INSERT #TB SELECT '1111','001','20121210',1234567,111.00
UNION ALL SELECT '2222','002','20121210',1234567,222.00
UNION ALL SELECT '3333','001','20121112',1234567,250.00
UNION ALL SELECT '4444','002','20121110',1234567,330.00
UNION ALL SELECT '5555','001','20121210',1234567,300.00
UNION ALL SELECT '6666','002','20121112',1234567,150.00
GO

--查询
SELECT A.ID
	,A.BANK_ID
	,A.AMT
	,B.OP_DATE
	,B.OPERATOR_NO
FROM
(
(SELECT 
	ID=CASE
		WHEN GROUPING(BANK_ID)=1 THEN '合计' 
		WHEN GROUPING(ID)=1 THEN '小计'
		ELSE ID END
	,BANK_ID
    ,SUM(AMT) AMT
    ,ORDER_SIGN1=GROUPING(BANK_ID),ORDER_SIGN2=BANK_ID
    ,ORDER_SIGN3=GROUPING(ID)
FROM #TB
GROUP BY BANK_ID,ID WITH ROLLUP
HAVING GROUPING(ID)=1
UNION ALL	--先得出表的统计，再加上表中的数据
SELECT ID
	,BANK_ID
	,AMT
	,ORDER_SIGN1=0,ORDER_SIGN2=BANK_ID
    ,ORDER_SIGN3=0
	FROM #TB) A
LEFT JOIN	--为了显示出OP_DATE、OPERATOR_NO
(SELECT ID
	,OP_DATE
	,OPERATOR_NO 
FROM #TB) B ON A.ID = B.ID
) ORDER BY ORDER_SIGN1,ORDER_SIGN2,ORDER_SIGN3,OP_DATE

GO

--删除测试
DROP TABLE #TB

/*--测试结果
ID	BANK_ID	AMT	OP_DATE	OPERATOR_NO
3333	001	250.00	20121112	1234567
5555	001	300.00	20121210	1234567
1111	001	111.00	20121210	1234567
小计	001	661.00	NULL	NULL
4444	002	330.00	20121110	1234567
6666	002	150.00	20121112	1234567
2222	002	222.00	20121210	1234567
小计	002	702.00	NULL	NULL
合计	NULL	1363.00	NULL	NULL
--*/