数据库有Score表的数据如下:
tname | subject | score |
stu1 | Chinese | 80 |
stu1 | English | 60 |
stu1 | Math | 75 |
stu2 | Chinese | 80 |
stu2 | English | 85 |
stu3 | Chinese | 85 |
stu3 | Math | 90 |
需要行列转换,获取下列视图:
tname |
Chinese |
English |
Math |
stu1 |
80 |
60 |
75 |
stu2 |
80 |
85 |
|
stu3 |
85 |
|
90 |
如何通过SQL代码实现呢? 下面针对SQL 2000/2005 分别给出了方法:
--SQL2000 静态 sql
SELECT tname,
Chinese = MAX(CASE subject WHEN 'Chinese' THEN score ELSE 0 END),
English = MAX(CASE subject WHEN 'English' THEN score ELSE 0 END),
Math = MAX(CASE subject WHEN 'Math' THEN score ELSE 0 END)
FROM teammember
GROUP BY tname
ORDER BY tname
--SQL2000 动态 sql
DECLARE @sql NVARCHAR(4000)
SET @sql = 'SELECT tname'
SELECT @sql = @sql + ', ' + a.subject + ' = MAX(CASE subject WHEN ''' + a.subject + ''' THEN score ELSE 0 END)'
FROM (SELECT DISTINCT subject FROM teammember) a ORDER BY subject
SET @sql = @sql + ' FROM teammember GROUP BY tname ORDER BY tname'
EXEC(@sql)
--SQL2005 静态 sql
SELECT * FROM (SELECT * FROM teammember) a PIVOT (MAX(score) FOR subject IN (Chinese, English, Math)) b
--SQL2005 动态 sql
DECLARE @sql NVARCHAR(4000)
SELECT @sql = ISNULL(@sql + ',' , '') + subject FROM teammember GROUP BY subject
EXEC ('SELECT * FROM (SELECT * FROM teammember) a PIVOT (MAX(score) FOR subject IN (' + @sql + ')) b')