Jquery UI Tree组件的json格式，java递归拼接demo

数据库中表数据，如下图：

实现的需求是，如果suporgcode数据为null 的情况下，表示在一级节点 "请选择" 的二级节点，然后是如：3和36 是1的子节点，一步一步的节点延伸

java代码拼接方式如下：

 /**
 	 * 拼接成json类型  事故类型  
 	 * @author 刘仁奎
 	 */
     public String createJSONData(String instcode){
     	// 查询一级节点
     	String sql="select orgcode,orgname,suporgcode from swe_emerplanorg where instcode='"+instcode+"' and suporgcode is null order by orgcode";
 		List list=jdbcT.queryForList(sql);
 		StringBuffer json=new StringBuffer("[{\"id\":\"0\",\"text\":\"请选择\",\"children\":[");	// 初始化根节点
 		if(list!=null && list.size()>0){
 			for(int i=0; i<list.size();i++){
 				Map v_map = (Map)list.get(i);
				json.append(this.getChildren(instcode,v_map.get("ORGCODE").toString()));	// 获取子节点
 			}
 			json=new StringBuffer(json.substring(0, json.length()-1)+"]}]");
     	}
 		System.out.println(json);
 		return json.toString();
 	}
     /**
      * 得到子节点
      */
     private String getChildren(String instcode,String orgcode){
    	String sql = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and orgcode='"+orgcode+"' and suporgcode is null order by orgcode";
 		List list=jdbcT.queryForList(sql);
 		StringBuffer child_json=new StringBuffer();
 		if(list!=null && list.size()>0){
 			for(int i=0; i<list.size();i++){
 				Map v_map = (Map)list.get(i);
 				child_json.append("{\"id\":\""+v_map.get("ORGCODE").toString().trim()+"\",");
 				child_json.append("\"text\":\""+v_map.get("ORGNAME").toString().trim()+"\"");
 				String sql_2 = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and suporgcode='"+v_map.get("ORGCODE")+"' order by orgcode";
 				List t_l=jdbcT.queryForList(sql_2);
 				if(t_l!=null && t_l.size()>0){
 					child_json.append(",\"children\":[");
 					for(int t=0; t<t_l.size();t++){
 	 					Map t_m = (Map)t_l.get(t);
 	 					child_json.append("{\"id\":\""+t_m.get("ORGCODE").toString().trim()+"\",");
 	 	 				child_json.append("\"text\":\""+t_m.get("ORGNAME").toString().trim()+"\"");
 	 	 				child_json.append(getNodes(instcode,t_m.get("ORGCODE").toString()));	// 下级节点
 					}
 					child_json=new StringBuffer(child_json.substring(0, child_json.lastIndexOf(","))+"]},");
 				}else{
 					child_json.append("},");
 				}
 			}
 		}else{
 			child_json.append("},");
 		}
     	return child_json.toString();
     }
     
     /**
      * 获得节点 
      */
     public String getNodes(String instcode,String orgcode){
    	String sql = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and suporgcode ='"+orgcode+"' order by orgcode";
  		List list=jdbcT.queryForList(sql);
  		StringBuffer j_s=new StringBuffer();
  		if(list!=null && list.size()>0){
  			j_s.append(",\"children\":[");
  			for(int i=0; i<list.size();i++){
  				Map t_m = (Map)list.get(i);
  	  			j_s.append("{\"id\":\""+t_m.get("ORGCODE").toString().trim()+"\",");
  	  			j_s.append("\"text\":\""+t_m.get("ORGNAME").toString().trim()+"\"");
  	  			j_s.append(getNodes(instcode,t_m.get("ORGCODE").toString()));
  			}
  		}else{
  			j_s.append("},");
  		}
  		if(j_s.toString().contains("children")){
  			j_s=new StringBuffer(j_s.substring(0, j_s.lastIndexOf(",")));
  			j_s.append("]},");
  		}
  		return j_s.toString();
     }

最终的实现图如下