智商真心捉急,这题一看到钩子和砝码的个数都小于20,就钻进状压的死胡同没出来了。囧……
其实也就是一个很简单的统计方案数,就是让砝码挂上去之后的力矩之和为0,负的就让他是负的好了。然后阶段维要留着,负数会造成完全背包的效果。然后就是处理一下负数,映射到大一点的区间就完事。分组背包也就是把阶段维留着的意思啊……囧……
/* Author : Speedcell Update : 2013-03-23 Version : soppYcell 2.1 */ #include <algorithm> #include <iostream> #include <fstream> #include <sstream> #include <iomanip> #include <map> #include <set> #include <list> #include <stack> #include <queue> #include <deque> #include <vector> #include <string> #include <bitset> #include <memory> #include <complex> #include <numeric> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> #include <time.h> #include <ctype.h> #include <locale.h> using namespace std; #pragma pack(4) #ifndef __CONSTANT__ #define __CONSTANT__ typedef long long LONG; const double pi = acos(-1.0); const int inf = 0x7f7f7f7f; const LONG INF = 0x7f7f7f7f7f7f7f7fll; const int go[8][2] = {{0,1},{0,-1},{1,0},{-1,0},{1,1},{1,-1},{-1,1},{-1,-1}}; #endif // __CONSTANT__ #ifndef __IO__ #define __IO__ inline bool RD(int & a) {return scanf("%d",&a)!=EOF;} inline bool RD(char & a) {return scanf("%c",&a)!=EOF;} inline bool RD(char * a) {return scanf("%s", a)!=EOF;} inline bool RD(double & a) {return scanf("%lf",&a)!=EOF;} inline bool RD(LONG & a) {return scanf("%I64d",&a)!=EOF;} template<class T1> inline bool IN(T1 & a) {return RD(a);} template<class T1,class T2> inline bool IN(T1 & a,T2 & b) {return RD(a)&&RD(b);} template<class T1,class T2,class T3> inline bool IN(T1 & a,T2 & b,T3 & c) {return RD(a)&&RD(b)&&RD(c);} template<class T1,class T2,class T3,class T4> inline bool IN(T1 & a,T2 & b,T3 & c,T4 & d) {return RD(a)&&RD(b)&&RD(c)&&RD(d);} template<class T1,class T2,class T3,class T4,class T5> inline bool IN(T1 & a,T2 & b,T3 & c,T4 & d,T5 & e) {return RD(a)&&RD(b)&&RD(c)&&RD(d)&&RD(e);} template<class T1,class T2,class T3,class T4,class T5,class T6> inline bool IN(T1 & a,T2 & b,T3 & c,T4 & d,T5 & e,T6 & f) {return RD(a)&&RD(b)&&RD(c)&&RD(d)&&RD(e)&&RD(f);} template<class T1,class T2,class T3,class T4,class T5,class T6,class T7> inline bool IN(T1 & a,T2 & b,T3 & c,T4 & d,T5 & e,T6 & f,T7 & g) {return RD(a)&&RD(b)&&RD(c)&&RD(d)&&RD(e)&&RD(f)&&RD(g);} inline void PT(int a) {printf("%d",a);} inline void PT(char a) {printf("%c",a);} inline void PT(double a) {printf("%f",a);} inline void PT(LONG a) {printf("%I64d",a);} inline void PT(string a) {printf("%s",a.begin());} template<class T1> inline void OT(T1 a) {PT(a);} template<class T1,class T2> inline void OT(T1 a,T2 b) {PT(a),PT(' '),PT(b);} template<class T1,class T2,class T3> inline void OT(T1 a,T2 b,T3 c) {PT(a),PT(' '),PT(b),PT(' '),PT(c);} template<class T1,class T2,class T3,class T4> inline void OT(T1 a,T2 b,T3 c,T4 d) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d);} template<class T1,class T2,class T3,class T4,class T5> inline void OT(T1 a,T2 b,T3 c,T4 d,T5 e) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PT(e);} template<class T1,class T2,class T3,class T4,class T5,class T6> inline void OT(T1 a,T2 b,T3 c,T4 d,T5 e,T6 f) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PT(e),PT(' '),PT(f);} template<class T1,class T2,class T3,class T4,class T5,class T6,class T7> inline void OT(T1 a,T2 b,T3 c,T4 d,T5 e,T6 f,T7 g) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PT(e),PT(' '),PT(f),PT(' '),PT(g);} inline void PL(int a) {printf("%d\n",a);} inline void PL(char a) {printf("%c\n",a);} inline void PL(double a) {printf("%f\n",a);} inline void PL(LONG a) {printf("%I64d\n",a);} inline void PL(string a) {printf("%s\n",a.begin());} template<class T1> inline void OL(T1 a) {PL(a);} template<class T1,class T2> inline void OL(T1 a,T2 b) {PT(a),PT(' '),PL(b);} template<class T1,class T2,class T3> inline void OL(T1 a,T2 b,T3 c) {PT(a),PT(' '),PT(b),PT(' '),PL(c);} template<class T1,class T2,class T3,class T4> inline void OL(T1 a,T2 b,T3 c,T4 d) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PL(d);} template<class T1,class T2,class T3,class T4,class T5> inline void OL(T1 a,T2 b,T3 c,T4 d,T5 e) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PL(e);} template<class T1,class T2,class T3,class T4,class T5,class T6> inline void OL(T1 a,T2 b,T3 c,T4 d,T5 e,T6 f) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PT(e),PT(' '),PL(f);} template<class T1,class T2,class T3,class T4,class T5,class T6,class T7> inline void OL(T1 a,T2 b,T3 c,T4 d,T5 e,T6 f,T7 g) {PT(a),PT(' '),PT(b),PT(' '),PT(c),PT(' '),PT(d),PT(' '),PT(e),PT(' '),PT(f),PT(' '),PL(g);} #endif // __IO__ #ifndef __MACRO__ #define __MACRO__ #define ML(times) int tcase; IN(tcase); FOR(times,1,tcase) #define FOR(i,a,b) for(int i=int(a),_##i=int(b);i<=_##i;i++) #define DWN(i,b,a) for(int i=int(b),_##i=int(a);_##i<=i;i--) #define ECH(i,u,pre,next) for(int i=int(pre[u]);i!=-1;i=int(next[i])) #define MEM(a,v) memset(a,v,sizeof(a)) #define CLR(a,v) FOR(_i##a,0,sizeof(a)/sizeof(a[0])-1) a[_i##a]=v #define LOOP(a,n) \ FOR(_i##a,0,n-1) \ cout<<a[_i##a]<<(_i##a!=n-1?' ':'\n') #define LOOP2(a,n,m) \ FOR(_i##a,0,n-1) FOR(_j##a,0,m-1) \ cout<<a[_i##a][_j##a]<<(_j##a!=m-1?' ':'\n') #define LOOPG(G,n,pre,next) \ FOR(_i##a,0,n-1) ECH(_j##a,_i##a,pre,next) \ cout<<_i##a<<" "<<G[_j##a].v<<" "<<G[_j##a].w<<endl #endif // __MACRO__ #ifndef __BIT__ #define __BIT__ template<class T> inline T lb(T i) {return i&-i;} template<class T> inline T lc(T i) {return i<<T(1);} template<class T> inline T rc(T i) {return i<<T(1)|T(1);} template<class T> inline T at(T a,int i) {return a& (T(1)<<i);} template<class T> inline T nt(T a,int i) {return a^ (T(1)<<i);} template<class T> inline T s1(T a,int i) {return a| (T(1)<<i);} template<class T> inline T s0(T a,int i) {return a&~(T(1)<<i);} #endif // __BIT__ #ifndef __DOUBLE__ #define __DOUBLE__ const double eps = 1e-8; inline int cmp(double a) {return fabs(a-0)<eps?0:((a-0)>eps?+1:-1);} inline int cmp(double a,double b) {return fabs(a-b)<eps?0:((a-b)>eps?+1:-1);} inline double fmax(double a,double b) {return cmp(a,b)>0?a:b;} inline double fmin(double a,double b) {return cmp(a,b)<0?a:b;} #endif // __DOUBLE__ const int MAXV = 21; const int MAXE = 7502; int n,m,p[MAXV],w[MAXV],dp[MAXV][MAXE*2]; int fix(int val) { return val+MAXE; } int main() { #ifndef ONLINE_JUDGE freopen("Balance.txt","r",stdin); #else #endif while(IN(n,m)) { FOR(i,0,n-1) IN(p[i]); FOR(j,0,m-1) IN(w[j]); MEM(dp,0); FOR(i,0,n-1) dp[0][fix(p[i]*w[0])]=1; FOR(j,1,m-1) FOR(i,0,n-1) { FOR(k,-MAXE,MAXE) { dp[j][fix(k)]+=dp[j-1][fix(k-p[i]*w[j])]; } } OL(dp[m-1][fix(0)]); } return 0; }