bzoj3172 [Tjoi2013]单词

题目链接

构造AC自动机

BFS更新答案

由于做完fail后有BFS序，直接用就可以了

 1 #include<algorithm>
 2 #include<iostream>
 3 #include<cstdlib>
 4 #include<cstring>
 5 #include<cstdio>
 6 #include<string>
 7 #include<cmath>
 8 #include<ctime>
 9 #include<queue>
10 #include<stack>
11 #include<map>
12 #include<set>
13 #define rre(i,r,l) for(int i=(r);i>=(l);i--)
14 #define re(i,l,r) for(int i=(l);i<=(r);i++)
15 #define Clear(a,b) memset(a,b,sizeof(a))
16 #define inout(x) printf("%d",(x))
17 #define douin(x) scanf("%lf",&x)
18 #define strin(x) scanf("%s",(x))
19 #define LLin(x) scanf("%lld",&x)
20 #define op operator
21 #define CSC main
22 typedef unsigned long long ULL;
23 typedef const int cint;
24 typedef long long LL;
25 using namespace std;
26 void inin(int &ret)
27 {
28     ret=0;int f=0;char ch=getchar();
29     while(ch<'0'||ch>'9'){if(ch=='-')f=1;ch=getchar();}
30     while(ch>='0'&&ch<='9')ret*=10,ret+=ch-'0',ch=getchar();
31     ret=f?-ret:ret;
32 }
33 int n;
34 char s[1000010];
35 int ch[1000010][26],ed,wei[222],sum[1000010],pre[1000010],sta[1000010],top;
36 void add(char *s,int id)
37 {
38     int x=0,len=strlen(s);
39     re(i,0,len-1)
40     {
41         int c=s[i]-'a';
42         if(!ch[x][c])ch[x][c]=++ed;
43         x=ch[x][c];
44         sum[x]++;
45     }
46     wei[id]=x;
47 }
48 queue<int>h;
49 void getfail()
50 {
51     re(i,0,25)if(ch[0][i])
52     {
53         h.push(ch[0][i]);
54         pre[ch[0][i]]=0;
55     }
56     while(!h.empty())
57     {
58         int x=h.front();h.pop();
59         sta[++top]=x;
60         re(i,0,25)
61         {
62             if(!ch[x][i])
63             {
64                 ch[x][i]=ch[pre[x]][i];
65                 continue;
66             }
67             int v=ch[x][i];
68             int k=pre[x];
69             pre[v]=ch[k][i];
70             h.push(v);
71         }
72     }
73 }
74 int main()
75 {
76     inin(n);
77     re(i,1,n)
78     {
79         strin(s);
80         add(s,i);
81     }
82     getfail();
83     while(top)
84         sum[pre[sta[top]]]+=sum[sta[top]],top--;
85     re(i,1,n)printf("%d\n",sum[wei[i]]);
86      return 0;
87 }