Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
这道题是典型的backtracking类题目,这类题目感觉起来有点枚举的感觉(把所有的情况列出来)。这类题有类似的处理方式,可以参看generate parentheses,有回溯的基本解释。
public List<List<Integer>> combine(int n, int k) { List<List<Integer>> res = new ArrayList<List<Integer>>(); List<Integer> item = new ArrayList<Integer>(); if (k > n || n <= 0 || k <= 0) { return res; } dfsHelper(res, item, 1, n, k); return res; } public void dfsHelper(List<List<Integer>> res, List<Integer> item, int start, int n, int k) { if (item.size() == k) { res.add(new ArrayList<Integer>(item)); return; } for (int i = start; i <= n; i++) { item.add(i); dfsHelper(res, item, i+1, n, k); item.remove(item.size() - 1); } }