HDU2001计算两点间的距离（C,Java用DecimalFormat格式控制）

计算两点间的距离

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 162829    Accepted Submission(s): 57801

Problem Description

输入两点坐标（X1,Y1）,（X2,Y2）,计算并输出两点间的距离。

 

Input

输入数据有多组，每组占一行，由4个实数组成，分别表示x1,y1,x2,y2,数据之间用空格隔开。

 

Output

对于每组输入数据，输出一行，结果保留两位小数。

 

Sample Input

   
   
   
   

    
    
    
    0 0 0 1
0 1 1 0
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    1.00
1.41
   
   
   
   

 

Author

lcy

 

Source

C语言程序设计练习（一）

 

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C语言AC代码：

#include <stdio.h>
#include <math.h>
int main()
{
    double x1,y1,x2,y2,d;
    while (scanf("%lf %lf %lf %lf",&x1,&y1,&x2,&y2)!=EOF)
    {
        d=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
        printf("%.2lf\n",d);
    }
    return 0;
}

Java AC代码：

import java.text.DecimalFormat;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		while(sc.hasNext()){
			double x1 = sc.nextDouble();
			double y1 = sc.nextDouble();
			double x2 = sc.nextDouble();
			double y2 = sc.nextDouble();
			
			double a =Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
			DecimalFormat df = new DecimalFormat("#0.00");
			
			System.out.println(df.format(a));
		}
	}

}