Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
create table Student(S# varchar(20),Sname varchar(10),Sage int,Ssex varchar(2))
前面加一列序号:
if
exists(select table_name from information_schema.tables
where table_name='Temp_Table')
drop table Temp_Table
go
select 排名=identity(int,1,1),* INTO Temp_Table from Student
go
select * from Temp_Table
go
drop database [ ] --删除空的没有名字的数据库
问题:
1、查询“”课程比“”课程成绩高的所有学生的学号;
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
from SC where C#='002') b
where a.score>b.score and a.s#=b.s#;
2、查询平均成绩大于分的同学的学号和平均成绩;
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、查询所有同学的学号、姓名、选课数、总成绩;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、查询姓“李”的老师的个数;
select count(distinct(Tname))
from Teacher
where Tname like '李%';
5、查询没学过“叶平”老师课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平');
6、查询学过“”并且也学过编号“”课程的同学的学号、姓名;
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='叶平'));
8、查询课程编号“”的成绩比课程编号“”课程低的所有同学的学号、姓名;
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、查询所有课程成绩小于分的同学的学号、姓名;
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、查询没有学全所有课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、查询至少有一门课与学号为“”的同学所学相同的同学的学号和姓名;
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、查询至少学过学号为“”同学所有一门课的其他同学学号和姓名;
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平');
14、查询和“”号的同学学习的课程完全相同的其他同学学号和姓名;
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、删除学习“叶平”老师课的SC表记录;
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平';
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“”课程的同学学号、、
号课的平均成绩;
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S# as 学生ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 数据库
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企业管理
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英语
,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) AS 平均成绩
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(),马克思(),OO&UML (),数据库()
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数
FROM SC
21、查询不同老师所教不同课程平均分从高到低显示
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、查询如下课程成绩第名到第名的学生成绩单:企业管理(),马克思(),UML (),数据库()
[学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩
SELECT DISTINCT top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名,
T1.score AS 企业管理,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as 课程ID, Cname as 课程名称
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24、查询学生平均成绩及其名次
SELECT 1+(SELECT COUNT( distinct 平均成绩)
FROM (SELECT S#,AVG(score) AS 平均成绩
FROM SC
GROUP BY S#
) AS T1
WHERE 平均成绩> T2.平均成绩) as 名次,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均成绩
FROM SC
GROUP BY S#
) AS T2
ORDER BY 平均成绩desc;
25、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、查询每门课程被选修的学生数
select c#,count(S#) from sc group by C#;
27、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#) AS 选课数
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、查询男生、女生人数
Select count(Ssex) as 男生人数from Student group by Ssex having Ssex='男';
Select count(Ssex) as 女生人数from Student group by Ssex having Ssex='女';
29、查询姓“张”的学生名单
SELECT Sname FROM Student WHERE Sname like '张%';
30、查询同名同性学生名单,并统计同名人数
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、查询平均成绩大于的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、查询课程名称为“数据库”,且分数低于的学生姓名和分数
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='数据库'and score <60;
35、查询所有学生的选课情况;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、查询任何一门课程成绩在分以上的姓名、课程名称和分数;
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、查询不及格的课程,并按课程号从大到小排列
select c# from sc where scor e <60 order by C# ;
38、查询课程编号为且课程成绩在分以上的学生的学号和姓名;
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
39、求选了课程的学生人数
select count(*) from sc;
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# );
41、查询各个课程及相应的选修人数
select count(*) from sc group by C#;
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、查询每门功成绩最好的前两名
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、统计每门课程的学生选修人数(超过人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select C# as 课程号,count(*) as 人数
from sc
group by C#
order by count(*) desc,c#
45、检索至少选修两门课程的学生学号
select S#
from sc
group by s#
having count(*) > = 2
46、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平');
48、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;
49、检索“”课程分数小于,按分数降序排列的同学学号
select S# from SC where C#='004'and score <60 order by score desc;
50、删除“”同学的“”课程的成绩
delete from Sc where S#='001'and C#='001';
学生表(学号、姓名、性别、年龄、所在系)
课程表(课程号、课程名、先修课号、学分)
学生选课表(学号、课程号、成绩)
--1:查询全体学生的学号和姓名
--2:查询全体学生的姓名、学号和所在系
--3: 查询全体学生的详细记录
--4: 查询全体学生的姓名及其出生年份
--5:查询全体学生姓名、出生年份和所在系,要求用小写字母表示所有系名
--6:查询选修了课程的学生学号
--7:查询计算机系(IS)所有学生的名单
--8:查询所有年龄在20以下学生的姓名和年龄
--9: 查询考试成绩有不及格的学生的学号
--10: 查询年龄在20-23 (包括20和23)之间的学生的姓名、系别和年龄
--11: 查询信息系(IS)、数学系(MA)和计算机科学系(CS)学生的姓名和性别
--12: 查询学号为95001的学生的详细情况
--13: 查询所有姓林的学生的姓名、学号和性别
--14: 查询姓“欧阳”且全名为三个汉字的学生的姓名
--15:查询名字中第二个字为“燕”字的学生姓名和学号
--16:查询所有不姓“刘”的学生的姓名
--17:查询课程名为“DB_DESIGN”的课程号的学分
--18:查询缺少成绩的学生的学号和相应的课程号(成绩字段值为Null)
--19: 查询所有有成绩的学生的学号和课程号
--20: 查询所有计算机系年龄在20以下的学生姓名
--21: 查询选修了3号课程的学生的学号和成绩,查询结果按分数降序排列
--22: 查询全体学生情况,查询结果按所在系的系号升序排列,同一系中的学生按年龄降序排列
--23: 查询学生总人数
--24: 查询选修了课程的学生人数
--25: 计算1号课程的学生的平均成绩
--26: 计算1号课程的学生的最高成绩分数
--27:求各个课程号及相应的选课人数
--28: 查询选修了三门以上课程的学生学号
--29:查询每个学生及其选修课情况
--30:查询每一门课的间接先行课
--31:选修2号课程且成绩在90以上的学生的学号和姓名
--32:查询每个学生的学号、姓名、选修的课程名及成绩
--33:查询与’林燕芳’在同一个系学习的学生姓名
--34: 查询其他系中比信息系某一学生小的学生姓名和年龄
--35:查询所有选修了1号课程的学生的学生姓名
--36:查询选修了全部课程的学生姓名
--37:至少选修了学生95002选修全部课程的学生号码
1:select Sno,Sname from Student
2:select Sno,Sname,Sdept from Student
3:select * from Student /*也可以逐一列出列名并用逗号分隔*/
--其中getdate是获取当前系统时间。这是一个获取到的结果 :2008-12-11 16:02:17.967
--datepart从获取到的系统时间中分离出需要的部分,这里是分离出年份,更多信息请查看SQL Server联机帮助
--下面的 出生年 指定了别名来替代原来结果页出现的文字
4:select Sname , (datepart( year,getdate())- Sage) '出生年' from Student
--该实例利用了小写转换函数lower() 提示:通过查询分析器的 公用对象 的 字符串函数中你可以找到这个函数
5:select Sname '姓名' , (datepart( year,getdate())- Sage) '出生年',lower(Sdept) '所在系' from Student
6:select Sno from sc --这里将返回全部结果,有重复的值
select distinct Sno from sc--加入关键字distinct就可以去除重复结果,只留1个
--sql 中默认对字符串大小写不敏感的,所以下面的sdept=’IS’你也可以写成sdept=’is’。如果你要启用大小写敏感,可以用下面的方法
if 敏感
select * from table where field1="AAA" COLLATE Chinese_PRC_CS_AS
else
select * from table where field1="AAA" COLLATE Chinese_PRC_CI_AS
COLLATE 的中文排序规则参数可用下列方式查到
SELECT * FROM ::fn_helpcollations() where name like 'Chinese%'
7: select Sname from student where sdept='IS'
8: select Sname,Sage from student where Sage<20
9: select Sno from sc where grade<60
--如果要查询不在这个区间的记录,那只要改成 not between就可以了
10:select Sname,Sdept,Sage from student where Sage between 20 and 23
--如果要查询不属于信息系、数学系和计算机科学系的,可以在in前面加上NOT
--也可以这样子写:select Sname,Ssex from student where Sdept='is' or sdept='ma' or sdept='cs'
11:select Sname,Ssex from student where Sdept in('IS','MA','CS')
--或者是select * from student where sno = '95001'
12: select * from student where sno like '95001':--like用于字符串匹配
--百分号匹配多个字符,包括0个
13: select Sname,Sno,Sage from student where sname like '林%'
-- 一个下划线匹配单个字符
14:select sname from student where sname like '欧阳_'
15:select sname,sno from student where sname like '_燕%'
16:select sname from student where sname not like '刘%'
17:select Ccredit from course where cname like 'DB/_DESIGN' escape'/'
--注意:这里不用使用 = null
18:select sno,cno from sc where grade is null
19:select sno,cno from sc where grade is not null
20: select sname from student where sdept='CS' and sage<20
21:select sno,grade from sc where cno=3 order by grade desc
22:select * from student order by sdept,sage desc
23::select count(*) from student
24:select count(distinct sno) from sc
25: select avg(grade) from sc where cno='1'
26: select max(grade) from sc where cno='1'
group by 按照它后面的列值进行分组,相同的值被分在一组
27: select cno,count(sno) from sc group by cno
--having后面的条件是根据group by 分组后的结果再进行筛选,最后只给出满足条件的分组
--where筛选的对象是整个表,而having则是分组
28: select sno from sc group by sno having count(sno)>=3
29:select a.sname,b.cno from student a ,sc b where a.sno=b.sno
或者
select a.sname,b.cno from student a left outer join sc b
on a.sno=b.sno where b.cno is not null
--自身连接
30:select a.Cno,b.Cpno from course a,course b where a.Cpno=b.Cno
--31:
select student.sno,student.sname
from student,sc
where student.sno=sc.sno and
sc.cno='2' and
sc.grade>=90
--32:
select student.sno,student.sname,course.cname,sc.grade
from (student left join sc on student.sno=sc.sno)
left join course on sc.cno=course.cno
或者:
--忽略cname和grade都为null的行
Select student.sno,sname,cname,grade
From student,sc,course
Where student.sno=sc.sno and sc.cno=course.cno
--33:
select sname from student
where sdept=(select sdept from student where sname='林燕芳')
--34:
select sname,sage
from student
where sage<any(
select sage from student
where sdept='is'
) and sdept<>'IS'
--35:利用 exists的查询
--exists根据是否存在行返回true/false
--如果要查询没有选修1号课程的学生姓名,只要使用NOT Exists即可
select *
from student
where exists(
select 1 from sc
where student.sno=sc.sno and cno='1'
)
或者你可以使用连接查询
select * from student left join sc on student.sno=sc.sno
where sc.cno='1'
--36:
declare @temp1 int
declare @temp2 int
select @temp1=count(*) from course
select @temp2=sno from sc group by sno
having count(sno)=@temp1
select sname from student where sno in (@temp2)
或者
--就是转换成查询没有一门课程没有选修的学生姓名
--如果把两个not都去掉就是查询所有有选修课程的学生
Select sname from student where not exists(
Select 1 from course where not exists(
Select 1 from sc where student.sno=sc.sno and course.cno=sc.cno
)
)
--37:
--同样要进行转换:查询这样的学生,没有95002选修的课程而学生X没有选修的
Select distinct sno
From sc scx
Where not exists
(
Select 1 from sc scy
Where scy.sno='95002' and not exists
(
Select 1 from sc scz
Where scz.sno=scx.sno and scz.cno=scy.cno
)
)
and sno!='95002'
插入语句:
1:对每一个系求平均年龄,并把结果存入数据库
需要创建一个表用来存储结果
Create table Deptage
(
Sdept char(15),
Avgage smallint
);
--插入子查询结果
insert into
Deptage(Sdept,Avgage)
select sdept,avg(sage)
from student
group by sdept
--查看结果
select * from deptage
修改语句;
1:将学生95001的年龄改为22岁
Update student
Set sage=22
Where sno='95001'--注意如果不带where,则修改全部记录
2:将所有的学生年龄加1岁(修改多个元组的值)
Update student
Set sage=sage+1;
3:将计算机系全体同学的成绩置零(带子查询的修改语句)
Update sc
Set grade=0
Where 'cs'=(
Select sdept from student
Where student.sno=sc.sno)
删除语句:
1:删除学号为95009的学生记录(删除后将无法回复)
Delete from student
Where sno='95009'--没有加where的话将删除该表全部记录
2:删除计算机科学系所有学生的选课记录
Delete from sc
Where 'cs'=(
Select sdept
From student
Where student.sno=sc.sno
)
例1:查询至少选秀1号课程和3号课程号的学生号码。
答案
select a.学号 from sc a,sc b where a.学号=b.学号 and a.课程号='1' and b.课程号='3'
例2:查询至少选修了一门直接先行课为5号课程的学生姓名。
答案:
select 姓名 from student where 学号 in( SELECT [学号] FROM [test].[dbo].[SC] where 课程号 in(SELECT 课程号 from Course where 先行课='5'))
例子3:查询选修了全部课程的学生号码和姓名。
declare @t1 int
declare @t2 int
select @t2=count(*) from Course
select @t1=学号 from SC group by 学号 having count(学号)=@t2
--print '@t1='+cast(@t1 as varchar)
Select 学号,姓名 from student where 学号=@t1
例子4:查询信息系年龄最大的三个学生的学号及其年龄,结果按年龄降序排列。
select top 3 学号,年龄 from Student where 所在系='IS' order by 年龄 desc
例子5:查询选修了2号课程的学生名字
select 姓名 from student where 学号 in( select 学号 from sc where 课程号=2)
例子6:查询成绩为90分以上的学生名字和课程名字
select st.姓名,c.课程名 from student st left join sc s on st.学号=s.学号 left join Course c on s.课程号=c.课程号
where st.学号 in (select st.学号 from sc where s.成绩>=90)
sql 取中间几条记录(select top 表达式)
--查询从第M条至N条的记录,写到存储过程中就是输入参数
declare @m int--
declare @n int--
declare @x int
declare @y int
--设置测试值
set @m=3
set @n=10
set @x=(@n-@m+1)
set @y=(@m-1)
/*
语法
Select top (n-(m-1)) * from [表名] where [parimary key] not in(select top (m-1)
[主键] from [表名] order by [排序字段及排序方法]) order by [排序字段及排序方法
];
*/
--测试用例,因为T-sql top 后不支持表达式,故采取下面的方法
exec('select top '+@x+'* from kf.T_Community where [C_ID] not in (select top '+@y+'
[C_ID] from kf.T_Community order by [C_ID]) order by [C_ID]')--PS:如果在Orcale中,可以直接通过rownumber来控制,这样就容易多了