oracle周数计算[转补]

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--日期计算,算第n周的第一天及最后一天是几号。  by keynes 2005.04.29
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-- ww的算法为每年1月1日为第一周开始,date+6为每一周结尾
-- 例如20090101为第一周的第一天,而第一周的最后一天为20090101+6=20090107
-- 公式 每周第一天  :date + 周 * 7 - 7
--      每周最后一天  :date + 周 * 7 - 1


-- 如果以ww格式为主,第1、17周的起迄如下
SQL>select to_date('20090101','yyyymmdd') + 1*7-7,to_date('20090101','yyyymmdd') + 1*7-1 from dual;

TO_DATE('20090101','YYYYMMDD')      TO_DATE('20090101','YYYYMMDD')
2009-01-01                                                     2009-01-07

 

SQL>select to_date('20090101','yyyymmdd') + 17*7-7,to_date('20090101','yyyymmdd') + 17*7-1 from dual;

          TO_DATE('20090101','YYYYMMDD')       TO_DATE('20090101','YYYYMMDD')
          2009-04-23                                                      2009-04-29

 

-- 验证如下
SQL>select to_char(to_date('20090422','yyyymmdd'),'ww') as weekn,

                    to_char(to_date('20090423','yyyymmdd'),'ww') as week1,

                    to_char(to_date('20090429','yyyymmdd'),'ww') as week2,

                    to_char(to_date('20090430','yyyymmdd'),'ww') as weekn2 from dual;

 

WEEKN    WEEK1     WEEK2    WEEKN2
16               17              17             18

 

-- iw的算法为星期一至星期日算一周,且每年的第一个星期一为第一周,
-- 例如20090101为星期六,所以用iw的算法是前年的53周,而20050103之后才是第一周的开始。
-- 公式 每周第一天  :next_day(date) + 周 * 7 - 7
--      每周最后一天:next_day(date) + 周 * 7 - 1
-- 如果以iw格式为主,第1、17周的起迄如下

 

SQL>select next_day(to_date('20090101','yyyymmdd'),'星期一')+ 1 * 7 - 7 as first_day,
          next_day(to_date('20090101','yyyymmdd'),2)+ 1 * 7 - 1 as last_day from dual;

         FIRST_DAY      LAST_DAY

          --------------------------------------
          2009-01-05         2009-01-11

 

SQL>select next_day(to_date('20090101','yyyymmdd'),'星期一')+ 17 * 7 - 7 as first_day,
          next_day(to_date('20090101','yyyymmdd'),2)+ 1 7* 7 - 1 as last_day from dual;

         FIRST_DAY      LAST_DAY

          --------------------------------------
          2009-04-27         2009-05-03

 

PS:NEXT_DAY   的用法,两个参数第1个是date,第2个是varchar2,返回date

SQL>select   next_day(sysdate,'星期一')   from   dual;

         NEXT_DAY(SYSDATE,'星期一')

          -------------------   
         2009-11-09 15:20:33

 

第2个参数可以是数字1-7,分别表示周日到周六   

SQL>   select   next_day(sysdate,7)   FROM   DUAL;   
         NEXT_DAY(SYSDATE,7)  
        -------------------   
         2009-11-07 15:19:12

或者更改设置:   
  SQL>   select   NEXT_DAY   (sysdate,   'MONDAY')   FROM   DUAL;   
  select   NEXT_DAY   (sysdate,   'MONDAY')   FROM   DUAL   
  ORA-01846:   周中的日无效  
   
  SQL>   alter   session   set   NLS_DATE_LANGUAGE   =   American;    
  Session   altered  
   
  SQL>   select   NEXT_DAY   (sysdate,   'MONDAY')   FROM   DUAL;      
  NEXT_DAY(SYSDATE,'MONDAY')  
  --------------------------  
  2005-9-26   10:50:25

 

其它:

----查今天是 "本月" 的第几周
SQL>SELECT TO_CHAR(SYSDATE,'WW') - TO_CHAR(TRUNC(SYSDATE,'MM'),'WW')  AS weekOfMon from dual;

SQL>SELECT TO_CHAR(SYSDATE,'W') AS weekOfMon from dual;

WEEKOFMON

--------------------------
1

----- 查今天是 "今年" 的第几周
select to_char(sysdate,'ww') from dual;

select to_char(sysdate,'iw') from dual;

TO_CHAR(SYSDATE,'IW')

--------------------------
45

附注:
上文所提之iw及ww格式在doc内解释如下
IW = Week of year (1-52 or 1-53) based on the ISO standard
WW = Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
 
参考文件:
Format Models:http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96540/sql_elements4a.htm#34512


 

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