题意:给出n个矩形的中心坐标以及长宽和相对于y轴的旋转角度,问矩形总面积与最小外围总面积的百分比(N组测试数据 <= 50,1< n <= 600,0 <= x, y, w, h <=10000, –90° < j <=90°)。
题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1593
——>>先求出矩形的顶点,然后求凸包求面积,求百分比。
#include <cstdio> #include <cmath> #include <algorithm> using namespace std; const int maxn = 2400 + 10; const double eps = 1e-10; int cnt; double totArea, recArea; int dcmp(double x){ if(fabs(x) < eps) return 0; else return x < 0 ? -1 : 1; } struct Point{ double x; double y; Point(double x = 0, double y = 0):x(x), y(y){} bool operator < (const Point& e) const{ return x < e.x || (dcmp(x - e.x) == 0 && y < e.y); } }p[maxn], q[maxn]; typedef Point Vector; Vector operator + (Point A, Point B){ return Vector(A.x + B.x, A.y + B.y); } Vector operator - (Point A, Point B){ return Vector(A.x - B.x, A.y - B.y); } Vector operator * (Point A, double p){ return Vector(A.x * p, A.y * p); } Vector operator / (Point A, double p){ return Vector(A.x / p, A.y / p); } double Cross(Vector A, Vector B){ return A.x * B.y - B.x * A.y; } double Area2(Point A, Point B, Point C){ return fabs(Cross(B-A, C-A)); } Vector Rotate(Vector A, double rad){ return Vector(A.x * cos(rad) - A.y * sin(rad), A.x * sin(rad) + A.y * cos(rad)); } int ConvexHull(Point *p, int n, Point* ch){ //Çó͹°ü sort(p, p + n); int m = 0; for(int i = 0; i < n; i++){ while(m > 1 && Cross(ch[m-1] - ch[m-2], p[i] - ch[m-2]) < 0) m--; ch[m++] = p[i]; } int k = m; for(int i = n-2; i >= 0; i--){ while(m > k && Cross(ch[m-1] - ch[m-2], p[i] - ch[m-2]) < 0) m--; ch[m++] = p[i]; } if(n > 1) m--; return m; } double ConvexPolygonArea(Point *p, int n){ double area = 0; for(int i = 1; i < n-1; i++) area += Area2(p[0], p[i], p[i+1]); return area / 2; } void init(){ totArea = recArea = cnt = 0; } int main() { int N, n; scanf("%d", &N); while(N--){ init(); double x, y, w, h, rad; scanf("%d", &n); for(int i = 0; i < n; i++){ scanf("%lf%lf%lf%lf%lf", &x, &y, &w, &h, &rad); rad *= acos(-1)/180; recArea += w * h; p[cnt++] = Rotate(Vector(-w/2, h/2), -rad) + Vector(x, y); p[cnt++] = Rotate(Vector(w/2, h/2), -rad) + Vector(x, y); p[cnt++] = Rotate(Vector(-w/2, -h/2), -rad) + Vector(x, y); p[cnt++] = Rotate(Vector(w/2, -h/2), -rad) + Vector(x, y); } int m = ConvexHull(p, cnt, q); totArea = ConvexPolygonArea(q, m); double ret = recArea / totArea * 100; printf("%.1f ", ret); puts("%"); } return 0; }