POJ2965 The Pilots Brothers' refrigerator(枚举)

http://poj.org/problem?id=2965


跟POJ1753相似,暴力枚举。我这里用了迭代加深。

#include <stdio.h>
#include <string.h>

int chess;
int step, flag;
int row[20], col[20];

inline void flip(int pos) {
    chess = chess^(1<<pos);
    for(int i=0; i<4; ++i)
        chess=chess^(1<<(pos/4*4 + i));
    for(int i=0; i<4; ++i)
        chess=chess^(1<<(pos%4 + i*4));
}

void dfs(int pos,int k) {
    if(k==step) {
        flag = (chess==0xFFFF);
        return ;
    }
    if(flag || pos>15) return;
    row[k] = pos/4;
    col[k] = pos%4;
    
    flip(pos);
    dfs(pos+1, k+1);
    flip(pos);
    dfs(pos+1, k);
}
int main() {
    int i,j;
    char temp[5];
    chess = 0;
    for(i=0; i<4; ++i) {
        scanf("%s",&temp);
        for(j=0; j<4; ++j)
            if(temp[j]=='-')
                chess = chess^(1<<(i*4+j));
    }
    flag = 0;
    for(step=0; step<=16; step++) { //迭代搜索深度
        dfs(0,0);
        if(flag)
            break;
    }
    printf("%d\n",step);
    for(i=0; i<step; ++i)
        printf("%d %d\n",row[i]+1,col[i]+1);
    return 0;
}

高效解法:http://poj.org/showmessage?message_id=156561


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