hdu1869-六度分离(floyd模板题)

/**  hdu1869 **/
#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<memory.h>
#include<map>
#include<queue>
#include <deque>
#include <list>
#include <ctime>
#include <stack>
#include <vector>
#include<set>
#define Maxn 105
typedef long long ll;
#define rep(i,j,n) for(int i=j;i<=n;i++)
#define per(i,j,k) for(int i=j;i>=k;--i)
#define lowbit(a) a&-a
#define Max(a,b) a>b?a:b
#define Min(a,b) a>b?b:a
const int inf = 0x3f3f3f3f;
const double pi = acos(-1.0);
using namespace std;
int map_p[Maxn][Maxn];
int n,m,x,y;
bool flag=true;
void Init()
{   rep(i,0,n-1)
       rep(j,0,n-1)
       i==j?map_p[i][j]=0:map_p[i][j]=inf;
}
void Floyd()
{   rep(k,0,n-1)
       rep(i,0,n-1)
          rep(j,0,n-1)
             map_p[i][j]>map_p[i][k]+map_p[k][j]?map_p[i][j]=map_p[i][k]+map_p[k][j]:map_p[i][j]=map_p[i][j];
}
int main()
{
    while(~scanf("%d%d",&n,&m))
    {   Init();
        flag=true;
        rep(i,1,m)
        {scanf("%d%d",&x,&y);
        map_p[x][y]=map_p[y][x]=1;
        }
        Floyd();
        rep(i,0,n-1)
           rep(j,0,n-1)
            if(map_p[i][j]>7) flag=false;
        if(flag)    printf("Yes\n");
        else        printf("No\n");
    }
    return 0;
}





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