Infinite Expressions for Pi

  • John Wallis (1655) took what can now be expressed as

    and without using the binomial theorem or integration (not invented yet) painstakingly came up with a formula for pi to be

    pi = 2*(2*2*4*4*6*6*...)/(1*3*3*5*5*7*...) .

  • William Brouncker (ca. 1660's) rewrote Wallis' formula as a continued fraction, which Wallis and later Euler (1775) proved to be equivalent. It is unknown how Brouncker himself came up with the continued fraction,

    Infinite Expressions for Pi_第1张图片 .

  • James Gregory (1671) & Gottfried Leibniz (1674) used the series expansion of the arctangent function,

    arctan(x) = x - (x^3)/3 + (x^5)/5 - (x^7)/7 + (x^9)/9 - (x^11)/11 + ... ,

    and the fact that arctan(1) = pi/4 to obtain the series

     .

    Unfortunately, this series converges to slowly to be useful, as it takes over 300 terms to obtain a 2 decimal place precision. To obtain 100 decimal places of pi, one would need to use at least 10^50 terms of this expansion!

  • History books credit Sir Isaac Newton (ca. 1730's) with using the series expansion of the arcsine function,

    arcsin(x) = x + (1*x^3)/(2*3) + (1*3*x^5)/(2*4*5) + (1*3*5*x^7)/(2*4*6*7) + ... ,

    and the fact that arctan(1/2) = pi/6 to obtain the series

     .

    This arcsine series converges much faster than using the arctangent. (Actually, Newton used a slightly different expansion in his original text.) This expansion only needed 22 terms to obtain 16 decimal places for pi.

  • Leonard Euler (1748) proved the following equivalent relations for the square of pi,

    PI的求法  PI=4*atan(1.0) - 风未定 - NGUNAUJ

    PI的求法  PI=4*atan(1.0) - 风未定 - NGUNAUJ

  • Ko Hayashi (1989) found another infinite expression for pi in terms of the Fibonacci numbers,

    PI的求法  PI=4*atan(1.0) - 风未定 - NGUNAUJ .
原文链接 http://www.geom.uiuc.edu/~huberty/math5337/groupe/expresspi.html
PI=atan(1.0)*4;

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