方法一:使用正则表达式,只保留常见字符
String wrongString = "sdfsa f,ds。";
String correct = wrongString.replaceAll("[^0-9a-zA-Z]J*","");匹配结果:
共找到 2 处匹配:
,
。
方法二:根据ASCII码匹配,去掉不合法的ASCII码
/** * 清除ASCII码中的换行符等特殊字符 * @param dirtyString * @return */ public static String cleanString(String dirtyString){ char[] charArray = dirtyString.toCharArray(); String cleanStr = ""; for (char charactor:charArray) { Integer[] wrongChar={1,2,3,4,5,6,7,8,12,13,14,15,16,17,18,19,20,12,22,23,24,25,26,27,28,29,30,31}; List<Integer> arr = Arrays.asList(wrongChar); Integer thisChar = new Integer(charactor); if(arr.contains(thisChar)){//如果包含非法字符,就跳过 JLogUtils.i("Alex","警告:该字符串包含非法ASCII字符"+dirtyString); continue; }else if(thisChar==10){//换行符处理,把换行符换成\n,修复不同android版本不兼容的问题 cleanStr = cleanStr.concat("\n"); }else {//正常字符 cleanStr = cleanStr.concat(String.valueOf(charactor)); } } return cleanStr; }
提供一个常用正则验证函数,只允许数字字母和空格
//判断是否是数字字母和空格 public static boolean checkInput(Context context, String str) { Pattern p = Pattern.compile("[a-zA-Z0-9\\s]*"); Matcher m = p.matcher(str); if (!m.find()) { return false; } else { if (m.group(0).length() != str.length()) { return false; } } return true; }