签到题,数据也比较小,直接dfs即可。你也可以用你喜欢的任一种方法AC。
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <cmath>
#include <ctime>
#include <vector>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
#define INF 0x3f3f3f3f
#define inf -0x3f3f3f3f
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define mem0(a) memset(a,0,sizeof(a))
#define mem1(a) memset(a,-1,sizeof(a))
#define mem(a, b) memset(a, b, sizeof(a))
typedef long long ll;
const int maxn=1001;
vector<int>G[maxn];
int tree[maxn];
int vis[maxn];
void dfs(int u){
vis[u]=1;
tree[u]=0;
for(int i=0;i<G[u].size();i++){
if(vis[G[u][i]]){
tree[u]=tree[u]+tree[G[u][i]]+1;
continue;
}
dfs(G[u][i]);
tree[u]=tree[u]+tree[G[u][i]]+1;
}
return ;
}
int main(){
int n,k;
//freopen("1011.in","r",stdin);
//freopen("1011.out","w",stdout);
while(scanf("%d%d",&n,&k)!=EOF){
for(int i=1;i<=n;i++)
G[i].clear();
int x,y;
for(int i=1;i<n;i++){
scanf("%d%d",&x,&y);
G[x].push_back(y);
}
mem0(vis);
mem0(tree);
for(int i=1;i<=n;i++){
if(!vis[i])
dfs(i);
}
int count1=0;
for(int i=1;i<=n;i++){
if(tree[i]==k)
count1++;
}
printf("%d\n",count1);
}
return 0;
}