Can you solve this equation?



Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

Sample Input

   
   
   
   

    
    
    
    2
100
-4
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    1.6152
No solution!
   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   


   
   
   
   
   
   
   
   

    
    
    
    
#include<stdio.h>
#include<math.h>
double fun(double x)
{
	return 8*pow(x,4)+7*pow(x,3)+2*pow(x,2)+3*x+6;
}
int main()
{
	int t;
	double y,mid;
	scanf("%d",&t);
	while(t--)
	{
		scanf("%lf",&y);
		if(fun(0)>y||fun(100)<y)   //怎么感觉应该是fun(0)>y 
		{
			printf("No solution!\n");
		}
		else
		{
			double l=0,r=100;
			while(r-l>1e-9)	//要保证精度 
			{
				mid=(r+l)/2;
				if(fun(mid)>y) r=mid;
				else l=mid;
			}
			printf("%.4lf\n",mid);
		}
	}
	return 0;
}
    
    
    
    

    
    
    
    

    
    
    
    
此问题刚开始可能找不到头脑，不知道从哪下手，重要的在于转化思想，用二分法做着实很有效。