POJ 1014 Dividing

#include <stdio.h>
#include <string.h>
int a[7],sum,b[100],n;
bool dp[60001];
int main()
{
    int i, j, k, t = 1, x;
    while (scanf ("%d%d%d%d%d%d", &a[1], &a[2], &a[3], &a[4], &a[5], &a[6]) != EOF)
    {
        if (a[1]+a[2]+a[3]+a[4]+a[5]+a[6]==0) break;
        printf("Collection #%d:/n", t++);
        sum=0;
        n=0;
        for (i=1;i<=6;i++)
        {
            sum+=a[i]*i;
            k=0;
            b[n++]=k*i;
            k++;
            x=0;
            while (x+k<a[i])
            {
                b[n++]=k*i;
                x+=k;
                k=k*2;
            }
            if (a[i]>x) b[n++]=(a[i]-x)*i;
        }
        if (sum%2)
  {
            printf ("Can't be divided./n/n");
            continue;
        }
        memset(dp,false,sizeof(dp));
        dp[0]=true;
        for (i=0;i<n;i++)
            for (j=sum/2;j>=b[i];j--)
                if (dp[j-b[i]]) dp[j]=true;
        if(dp[sum/2]) printf ("Can be divided./n/n");
        else printf ("Can't be divided./n/n");
    }
    return 0;
}

你可能感兴趣的:(ini,include)