Spoj 1716 Can you answer these queries III

(几乎一样的题和几乎一样的代码


#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;

const int maxn = 112345;

#define LL long long
const LL INFF = 0x3f3f3f3f3f3f3f3fll;

struct Info{
    LL lmax,rmax,sum,val;
    void maintain(LL x){
        lmax=rmax=sum=val=x;
    }
    Info(){
        maintain(-INFF);
        sum=0;
    }
};

Info operator + (const Info & a,const Info & b){
    Info ret;
    ret.sum=a.sum+b.sum;
    ret.lmax=max(a.lmax,a.sum+b.lmax);
    ret.rmax=max(b.rmax,b.sum+a.rmax);
    ret.val=max(max(a.val,b.val),a.rmax+b.lmax);
    return ret;
}

#define lson o<<1,l,m
#define rson o<<1|1,m+1,r
#define root 1,1,n
#define Now int o,int l,int r
#define Mid int m = l + (r-l)/2

Info sarr[maxn*4];

void update(Now,int p,LL v){
    if(l==r){
        sarr[o].maintain(v);
        return;
    }
    Mid;
    if(p<=m) update(lson,p,v);
    else update(rson,p,v);
    sarr[o]=sarr[o<<1]+sarr[o<<1|1];
}

Info query(Now,int ql,int qr){
    if(ql<=l && r<=qr){
        return sarr[o];
    }
    Mid;
    Info ret;
    if(ql<=m) ret = query(lson,ql,qr) + ret;
    if(m+1<=qr) ret = ret + query(rson,ql,qr);
    return ret;
}

int main(){
    int n;
    while(~scanf("%d",&n)){
        LL x;
        for(int i=1;i<=n;i++){
            scanf("%lld",&x);
            update(root,i,x);
        }
        int m;
        scanf("%d",&m);
        int l,r,p,ord;
        while(m--){
            scanf("%d",&ord);
            if(ord==1){
                scanf("%d %d",&l,&r);
                printf("%lld\n",query(root,l,r).val);
            }
            else{
                scanf("%d %lld",&p,&x);
                update(root,p,x);
            }
        }
    }
    return 0;
}





你可能感兴趣的:(Spoj 1716 Can you answer these queries III)