采用交叉编译的时候，报了这个错误，原来直接在Fedora下面编译没有问题。
原因在于编译器默认char的类型为unsigned类型，和0进行比较时总是true。
这个错误发生在stdsoap2.c文件中（104行的宏定义）
找个一个网上的代码加以说明：
I have the following code
//Point.h
#define WIDTH 8
#define HEIGHT 8
typedef struct Point
{
char x;
char y;
} Point;
//Board.c
#include <stdbool.h>
// Some other functions that we don't care about...
bool inBounds(Point * p)
{
return p->x >= 0
&& p->x <= WIDTH
&& p->y >= 0
&& p->y <= HEIGHT;
}
When I compile this (ppu-gcc 4.1.1), I get the following warning
warning: comparison is always true due to limited range of data type
even though the range of char is -127 to 127 and WIDTH is 8, which is well inside the range of a char. I've already tried an explicit cast of WIDTH to a char, but still got the error.
我找出了几个有用的回答：
The C and C++ standards allows the character type char to be signed or unsigned, depending on the platform and compiler. Most systems, including x86 GNU/Linux and Microsoft Windows, use signed char, but those based on PowerPC and ARM processors typically use unsigned char.(29) This can lead to unexpected results when porting programs between platforms which have different defaults for the type of char.
The char type may be signed or unsigned. It depends on your compiler vendor's choice. There might even be a compiler option available. Evidently,char is unsigned for you, so it's always greater than or equal to zero, and thus the compiler warns you.
You're using char here to represent "a numeric type that takes up minimal memory." In that case, I recommend explicitly usingsigned char orunsigned char. (Each is distinct from plainchar, despitechar having to be either signed or unsigned.) Reservechar for when you're holding character data. For numeric data, use one of the other two types.
源地址在这里
