Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Given the list [[1,1],2,[1,1]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,1,2,1,1]
.
Example 2:
Given the list [1,[4,[6]]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,4,6]
.
【思路】建一个栈,从list尾巴倒序压入栈中,每次检测栈顶,如果是整数元素,直接弹出;如果是向量,则将整个向量先弹出,再倒序压入每一个向量中的元素。
/** * // This is the interface that allows for creating nested lists. * // You should not implement it, or speculate about its implementation * class NestedInteger { * public: * // Return true if this NestedInteger holds a single integer, rather than a nested list. * bool isInteger() const; * * // Return the single integer that this NestedInteger holds, if it holds a single integer * // The result is undefined if this NestedInteger holds a nested list * int getInteger() const; * * // Return the nested list that this NestedInteger holds, if it holds a nested list * // The result is undefined if this NestedInteger holds a single integer * const vector<NestedInteger> &getList() const; * }; */ class NestedIterator { public: NestedIterator(vector<NestedInteger> &nestedList) { for(int i = nestedList.size()-1; i>=0; i--) { stk.push(nestedList[i]); } } int next() { int val; if(hasNext()) { val = stk.top().getInteger(); stk.pop(); } return val; } bool hasNext() { while(!stk.empty()) { NestedInteger tmp = stk.top(); if(tmp.isInteger()) return true; else{ vector<NestedInteger> tmpList = stk.top().getList(); stk.pop(); for(int j = tmpList.size()-1; j>=0; j--) { stk.push(tmpList[j]); } } } return false; } private: stack<NestedInteger>stk; }; /** * Your NestedIterator object will be instantiated and called as such: * NestedIterator i(nestedList); * while (i.hasNext()) cout << i.next(); */