GPS经纬度坐标的转换

wgs84:国家默认标准坐标

/gcj02:火星坐标

/bd09:百度坐标

转换方法:

<strong><span style="color:#ff6666;">Gps实体</span></strong>

public class Gps {

	public double wgLat;
	public double wgLon;

	public Gps(double wgLat, double wgLon) {
		setWgLat(wgLat);
		setWgLon(wgLon);
	}

	public double getWgLat() {
		return wgLat;
	}

	public void setWgLat(double wgLat) {
		this.wgLat = wgLat;
	}

	public double getWgLon() {
		return wgLon;
	}

	public void setWgLon(double wgLon) {
		this.wgLon = wgLon;
	}

	@Override
	public String toString() {
		return wgLat + "," + wgLon;
	}
}

<strong><span style="color:#ff6666;">经纬度转换</span></strong>

public class PositionUtil {
	
	//转换火星坐标密钥
	public double pi = 3.1415926535897932384626;
	public double a = 6378245.0;
	public double ee = 0.00669342162296594323;
	
	/**
	 * 84 to 火星坐标系 (GCJ-02) World Geodetic System ==> Mars Geodetic System
	 * 
	 * @param lat
	 * @param lon
	 * @return
	 */
	public Gps gps84_To_Gcj02(double lat, double lon) {
		if (outOfChina(lat, lon)) {
			return null;
		}
		double dLat = transformLat(lon - 105.0, lat - 35.0);
		double dLon = transformLon(lon - 105.0, lat - 35.0);
		double radLat = lat / 180.0 * pi;
		double magic = Math.sin(radLat);
		magic = 1 - ee * magic * magic;
		double sqrtMagic = Math.sqrt(magic);
		dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
		dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
		double mgLat = lat + dLat;
		double mgLon = lon + dLon;
		return new Gps(mgLat, mgLon);
	}
	
	public boolean outOfChina(double lat, double lon) {
		if (lon < 72.004 || lon > 137.8347)
			return true;
		if (lat < 0.8293 || lat > 55.8271)
			return true;
		return false;
	}

	public double transformLat(double x, double y) {
		double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y
				+ 0.2 * Math.sqrt(Math.abs(x));
		ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
		ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;
		ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;
		return ret;
	}

	public double transformLon(double x, double y) {
		double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1
				* Math.sqrt(Math.abs(x));
		ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;
		ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;
		ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0
				* pi)) * 2.0 / 3.0;
		return ret;
	}
}