HDU 1542 Atlantis (矩形面积并)

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1542

刚刚学会的矩形面积并,从下往上扫描,对x坐标离散化,在离散化后的x坐标上建立线段树,对于每条线段,二分找到左右端点,然后不断更新线段并统计面积

代码:

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<vector>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
const int MAXN=1010;
struct line{
    double h,l,r;
    int f;
    line(){}
    line(double a,double b,double c,int d):h(a),l(b),r(c),f(d){}
}seg[MAXN];
struct Tree{
    double len;
    int cover;
}sum[MAXN*3];
double xs[MAXN];
int linecnt,xcnt;
inline bool cmp(line a,line b){
    return a.h<b.h;
}
void addline(double x1,double y1,double x2,double y2){
    xs[++linecnt]=x1;seg[linecnt]=line(y1,x1,x2,1);
    xs[++linecnt]=x2;seg[linecnt]=line(y2,x1,x2,-1);
}
int Search(double k,int l,int r){
    while(l<=r){
        int m=(l+r)>>1;
        if(xs[m]==k)return m;
        if(xs[m]>k)r=m-1;
        else l=m+1;
    }
    return l;
}
inline void pushup(int rt,int l,int r){
    if(sum[rt].cover)sum[rt].len=xs[r+1]-xs[l];
    else if(l==r)sum[rt].len=0;
    else sum[rt].len=sum[rt<<1].len+sum[rt<<1|1].len;
}
void update(int L,int R,int c,int l,int r,int rt){
    if(L<=l&&r<=R){
        sum[rt].cover+=c;
        pushup(rt,l,r);
        return;
    }
    int m=(l+r)>>1;
    if(L<=m)update(L,R,c,lson);
    if(R>m)update(L,R,c,rson);
    pushup(rt,l,r);
}
int main(){
//    freopen("D://input.txt","r",stdin);
    int n,kase=1;
    while(scanf("%d",&n)!=EOF&&n){
        printf("Test case #%d\nTotal explored area: ",kase++);
        linecnt=xcnt=0;int i;
        while(n--){
            double xx[2],yy[2];
            scanf("%lf%lf%lf%lf",&xx[0],&yy[0],&xx[1],&yy[1]);
            addline(xx[0],yy[0],xx[1],yy[1]);
        }
        sort(seg+1,seg+linecnt+1,cmp);sort(xs+1,xs+linecnt+1);
        memset(sum,0,sizeof(sum));
        for(i=1;i<=linecnt;i++){
            if(xs[i+1]!=xs[i])
                xs[++xcnt]=xs[i];
        }
        double area=0;
        for(i=1;i<linecnt;i++){
            int L=Search(seg[i].l,1,xcnt),R=Search(seg[i].r,1,xcnt)-1;
            if(L<=R){
                update(L,R,seg[i].f,1,xcnt,1);
                area+=sum[1].len*(seg[i+1].h-seg[i].h);
            }
        }
        printf("%.2f\n\n",area);
    }
    return 0;
}


你可能感兴趣的:(HDU 1542 Atlantis (矩形面积并))