AIM Tech Round (Div. 2)--A. Save Luke

A. Save Luke
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Luke Skywalker got locked up in a rubbish shredder between two presses. R2D2 is already working on his rescue, but Luke needs to stay alive as long as possible. For simplicity we will assume that everything happens on a straight line, the presses are initially at coordinates0 and L, and they move towards each other with speed v1 and v2, respectively. Luke has width d and is able to choose any position between the presses. Luke dies as soon as the distance between the presses is less than his width. Your task is to determine for how long Luke can stay alive.

Input

The first line of the input contains four integers dLv1v2 (1 ≤ d, L, v1, v2 ≤ 10 000, d < L) — Luke's width, the initial position of the second press and the speed of the first and second presses, respectively.

Output

Print a single real value — the maximum period of time Luke can stay alive for. Your answer will be considered correct if its absolute or relative error does not exceed 10 - 6.

Namely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer correct, if .

Sample test(s)
input
2 6 2 2
output
1.000000
input
1 9 1 2
output
2.666667
Note

很简单的一道题目:
直接让v1走的距离加上v2走的距离加上宽度等于L即可!

#include<iostream>
#include<cmath>
#include<cstdio>
using namespace std;
int main()
{
    int d,L,v1,v2;
    while(scanf("%d%d%d%d",&d,&L,&v1,&v2) == 4){
        double ans = (L - d) * 1.0 / (v1+v2);
        printf("%.10lf\n",ans);
    }
    return 0;
}


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