poj 1258

水过一道最小生成树模板题,洗衣睡觉。。

/*
poj_1258    最小生成树
简单题,直接套模板。。以下为用kruskal的实现

不懂这句话到底有什么用:
Physically, they are limited in length to 80 characters, so some lines continue onto others.
*/
#include <iostream>
#include <string.h>
#include <cstdio>
#include <queue>
using namespace std;
struct node
{
    node( int i=0,int j=0,int k=0 )
    {
        from=i; to=j; value=k;
    }
    int from,to,value;
};
priority_queue <node> p;
int father[200],sum;

bool operator<( const node &a,const node &b )
{
    return a.value>b.value;
}

int find_set( int a )
{
    if( a!=father[a] )
    {
        father[a]=find_set( father[a] );
    }
    return father[a];
}

void union_set( int a,int b,int v )
{
    if( a==b )  return;
    father[b]=a;
    sum+=v;
}

int main()
{
    int n,i,j,temp;
    node t;
    while( scanf( "%d",&n )!=EOF )
    {
        for( i=0;i<n;i++ )
            father[i]=i;
        for( i=0;i<n;i++ )
        {
            for( j=0;j<n;j++ )
            {
                scanf( "%d",&temp );
                if( temp!=0 ) p.push( node( i,j,temp ) );
            }
        }
        sum=0;
        while( !p.empty() )
        {
            t=p.top();  p.pop();
            union_set( find_set(t.from),find_set(t.to),t.value );
        }
        printf( "%d\n",sum );
    }
    return 0;
}


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