c++ curl模拟登陆

转自:http://blog.csdn.net/zengraoli/article/details/11522647

我们在使用一些网站时，输入用户名，密码即可登陆该网站，登陆原理就是将用户输入的用户名和密码组合成一个特定字符串，post给一个url地址，如果用户名密码正确，就可以登陆了，如果想使用程序模拟这种登陆过程，需要下面的步骤：

1 抓包工具，推荐使用HttpWatch专业版，输入用户名，密码就开始抓包，并从包的内容中分析出post的url地址和post的内容，下面是我分析的（举例说明，不是实际情况）
url地址：https://loginchina.abc.com/member/signin.htm
post内容：action=Signin&eventSubmitDoPost=any&Done=http://china.abc.com/&urlType=&formSubmit=Y&LoginId="用户名"&Password="密码"

2写程序：下面是关键的部分程序

 int post_page_content(char* url)
 {

   m_chunk.memory = (char*)malloc(1);
   m_chunk.size = 0;

   curl_easy_setopt(curl_handle, CURLOPT_URL, url);
   curl_easy_setopt(curl_handle, CURLOPT_SSL_VERIFYPEER, 0);
   curl_easy_setopt(curl_handle, CURLOPT_SSL_VERIFYHOST, 1);
   curl_easy_setopt(curl_handle, CURLOPT_FOLLOWLOCATION, true);
   curl_easy_setopt(curl_handle, CURLOPT_COOKIEJAR, "mycookie.txt");
   curl_easy_setopt(curl_handle, CURLOPT_COOKIEFILE, "mycookie.txt");


   curl_easy_setopt(curl_handle, CURLOPT_WRITEFUNCTION, WriteMemoryCallback);


   curl_easy_setopt(curl_handle, CURLOPT_WRITEDATA, (void *)&m_chunk);


   curl_easy_setopt(curl_handle,          CURLOPT_POSTFIELDS,"action=Signin&eventSubmitDoPost=any&Done=http://china.abc.com/&urlType=&formSubmit=Y&LoginId="用户名"&Password="密码"");
  curl_easy_setopt(curl_handle, CURLOPT_USERAGENT, "libcurl-agent/1.0");


   curl_easy_perform(curl_handle);
    return 1;
 }
 char *myurl = "https://loginchina.abc.com/member/signin.htm";
 post_page_content(myurl);

经过这两个步，c++程序就可以模拟登陆了