经过一晚上把论文上面的东西全部试着证明了一遍搞明白了卷积= =
实际上是因为昨天连FWT求卷积的题都出来了,如果连FFT都不会的话还是人?
Problem : 1402 ( A * B Problem Plus ) Judge Status : Accepted RunId : 16778031 Language : G++ Author : BPMThor Code Render Status : Rendered By HDOJ G++ Code Render Version 0.01 Beta /* *********************************************** Author :BPM136 Created Time :2016/4/5 18:25:52 File Name :1402.cpp ************************************************ */ #include<stdio.h> #include<iostream> #include<cmath> #include<cstring> #define LL long long #define fo(i,a,b) for(int i=a;i<=b;i++) #define fd(i,a,b) for(int i=a;i>=b;i--) #define efo(i,x) for(int i=last[x];i!=0;i=e[i].next) using namespace std; LL read() { LL d=0,f=1;char s=getchar(); while(s<48||s>57){if(s==45)f=-1;s=getchar();} while(s>=48&&s<=57){d=d*10+s-48;s=getchar();} return d*f; } #define DB double struct comple { DB r,i; comple(DB x=0.0,DB y=0.0) { r=x,i=y; } comple operator+(comple &a)const { return comple(r+a.r,i+a.i); } comple operator-(comple &a)const { return comple(r-a.r,i-a.i); } comple operator*(comple &a)const { return comple((DB)r*a.r-i*a.i,(DB)r*a.i+i*a.r); } }; void change(comple y[],int len) { int i,j,k; for(i=1,j=len/2;i<len-1;i++) { if(i<j)swap(y[i],y[j]); k=len>>1; while(j>=k) { j-=k; k>>=1; } if(j<k)j+=k; } } const DB pi=3.1415926525; void FFT(comple y[],int len,int on) { change(y,len); for(int n=2;n<=len;n<<=1) { comple w(cos(-on*2*pi/n),sin(-on*2*pi/n)); for(int j=0;j<len;j+=n) { comple wt(1,0); for(int k=j;k<j+n/2;k++) { comple u=y[k]; comple v=wt*y[k+n/2]; y[k]=u+v; y[k+n/2]=u-v; wt=wt*w; } } } if(on==-1)fo(i,0,len-1)y[i].r/=len; } #define N 200005 comple x1[N],x2[N]; char str1[N],str2[N]; int sum[N]; int n,m; int main() { //freopen(".in","r",stdin); //freopen(".out","w",stdout); while(scanf("%s%s",str1,str2)!=EOF) { int len1=strlen(str1),len2=strlen(str2); int len;for(len=1;len<len1*2||len<len2*2;len<<=1); fo(i,0,len1-1)x1[i]=comple(str1[len1-i-1]-'0',0); fo(i,len1,len)x1[i]=comple(0,0); fo(i,0,len2-1)x2[i]=comple(str2[len2-i-1]-'0',0); fo(i,len2,len)x2[i]=comple(0,0); FFT(x1,len,1);FFT(x2,len,1); fo(i,0,len-1)x1[i]=x1[i]*x2[i]; FFT(x1,len,-1); fo(i,0,len-1)sum[i]=(int)(x1[i].r+0.5); fo(i,0,len-1)sum[i+1]+=sum[i]/10,sum[i]%=10; for(len=len1+len2-1;sum[len]<=0&&len;len--); fd(i,len,0)putchar((char)sum[i]+'0');putchar('\n'); } return 0; }