codeforces 30C Shooting Gallery (概率dp)

题意:

给出n个会定时出现的靶子,每个靶子给出出现的时间坐标和能打中概率,问打中靶子数的期望最大值。

题解:

简单的概率dp,dp[i]表示以i为结尾打中靶子数期望的最大值。注意精度!

#include<iostream>
#include<math.h>
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<vector>
#include<map>
using namespace std;
typedef long long lld;
const int oo=0x3f3f3f3f;
const lld OO=1LL<<61;
const int MOD=1000000007;
#define eps 1e-6
#define maxn 1005
double dp[maxn];
struct NODE
{
    double x,y,t,p;
}a[maxn];

bool cmp(NODE n1,NODE n2)
{
    return n1.t<n2.t-eps;
}

double dis(NODE n1,NODE n2)
{
    return sqrt(1.0*(n1.x-n2.x)*(n1.x-n2.x)+1.0*(n1.y-n2.y)*(n1.y-n2.y));
}

int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        for(int i=1;i<=n;i++)
            scanf("%lf %lf %lf %lf",&a[i].x,&a[i].y,&a[i].t,&a[i].p);
        sort(a+1,a+1+n,cmp);
        memset(dp,0,sizeof dp);
        dp[0]=0.0;
        double ans=0.0;
        for(int i=1;i<=n;i++)
        {
            for(int j=0;j<i;j++)
            if(a[i].t-a[j].t>dis(a[j],a[i])-eps||j==0)
            {
                dp[i]=max(dp[i],dp[j]+a[i].p);
            }
            ans=max(ans,dp[i]);
        }
        printf("%.10lf\n",ans);
    }
    return 0;
}
/**
1
0 0 0 0.5
2
0 0 0 0.6
5 0 5 0.7

*/








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