周赛一 CodeForces 479A

Description

Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers a, b, c on the blackboard. The task was to insert signs of operations '+' and '*', and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:

• 1+2*3=7
• 1*(2+3)=5
• 1*2*3=6
• (1+2)*3=9

Note that you can insert operation signs only between a and b, and between b and c, that is, you cannot swap integers. For instance, in the given sample you cannot get expression (1+3)*2.

It's easy to see that the maximum value that you can obtain is 9.

Your task is: given a, b and c print the maximum value that you can get.

Input

The input contains three integers a, b and c, each on a single line (1 ≤ a, b, c ≤ 10).

Output

Print the maximum value of the expression that you can obtain.

Sample Input

Input

1
2
3

Output

9

Input

2
10
3

Output

60

#include<iostream>
#include<cstdio>

using namespace std;

int main()
{
	int a,b,c;
	while(~scanf("%d%d%d",&a,&b,&c))
	{
		int Max=a+b*c;
		int A,B,C,E,D;
		A=a*(b+c);
		B=a*b*c;
		C=(a+b)*c;
		D=a+b+c;
		E=a*b+c;
		if(Max<A)
			Max=A;
		if(Max<B)
			Max=B;
		if(Max<C)
			Max=C;
		if(Max<D)
			Max=D;
			if(Max<E)
				Max=E;
		printf("%d\n",Max);
	}

}
//读清题是让*+随意组合,读题是可不能太大意<span id="transmark"></span>