Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead.
For example, given the array [2,3,1,2,4,3]
and s = 7
,
the subarray [4,3]
has the minimal length under the problem constraint.
class Solution { public: int minSubArrayLen(int s, vector<int>& nums) { int n = nums.size(); if (n < 1) { return 0; } int result = n+1; int sum = 0; int left = 0; int right = 0; while (right < n) { sum += nums[right]; if (sum >= s) { while (sum >= s) { int temp = right-left+1; if (temp < result) { result = temp; } sum -= nums[left]; left++; } } right++; } if (result > n) { return 0; } return result; } };