Letter Combinations of a Phone Number
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Given a digit string, return all possible letter combinations that the number could represent.
A mapping of digit to letters (just like on the telephone buttons) is given below.
Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].
Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.
【解题思路】
还是最基本的DFS,但是有一点需要注意,输入有可能为"",这个比较变态,感觉这个不应该是考点之一。
将数字和字符的对应关系组成了一个数组
String array[] = {"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};
这样处理起来相对要方便些。特别要注意digits中为数字的再转换,否则的话继续。
Java AC
public class Solution { public String array[] = {"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"}; public ArrayList<String> letterCombinations(String digits) { ArrayList<String> list = new ArrayList<String>(); if(digits == null){ return list; } char numArr[] = digits.toCharArray(); int len = digits.length(); StringBuffer sb = new StringBuffer(); dfs(list,sb,0,numArr,len); return list; } public void dfs(ArrayList<String> list,StringBuffer sb, int tempLen,char numArr[],int len){ if(tempLen == len){ list.add(sb.toString()); return; } if(numArr[tempLen] >= '0' && numArr[tempLen] <= '9' ){ String tempStr = array[numArr[tempLen] - '0']; int strLen = tempStr.length(); for(int i = 0; i < strLen; i++){ StringBuffer newsb = new StringBuffer(sb); newsb.append(String.valueOf(tempStr.charAt(i))); dfs(list,newsb,tempLen+1,numArr,len); } }else{ StringBuffer newsb = new StringBuffer(sb); newsb.append(String.valueOf(numArr[tempLen])); dfs(list,newsb,tempLen+1,numArr,len); } } }