FatMouse's Speed

http://acm.hdu.edu.cn/showproblem.php?pid=1160

 

用类似求最长不减子序列的方法，比较水，转移方程为:f[n] = max(f[n], f[i] + 1)-----满足w[n] > w[i] && s[n] < s[i];

刚开始WA了几次，因为没注意到是严格单调增的

#include <iostream> #include <cstring> #include <algorithm> using namespace std; struct node { int w; int s; int num; }data[1010]; int pre[1010]; int len[1010]; bool cmp(const node& A, const node& B) { if(A.w != B.w) return A.w < B.w; return A.s > B.s; } void print(int index) { if(len[index] == 1) { cout << data[index].num << endl; return; } print(pre[index]); cout << data[index].num << endl; } int main() { //freopen("1.txt", "r", stdin); int n = 0; while(cin >> data[n].w >> data[n].s) { data[n].num = n + 1; n++; } sort(data, data + n, cmp); memset(pre, 0, sizeof(pre)); for(int i = 0; i < n; i++) len[i] = 1; for(int i = 1; i < n; i++) { for(int j = 0; j < i; j++) { if(data[j].w != data[i].w && data[j].s > data[i].s) { int tmpLen = len[j] + 1; if(tmpLen > len[i]) { len[i] = tmpLen; pre[i] = j; } } } } int index = 0; for(int i = 1; i < n; i++) if(len[i] > len[index]) index = i; cout << len[index] << endl; print(index); return 0; }