Bone Collector 2602 01背包问题

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?
Bone Collector 2602 01背包问题_第1张图片

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.


Output

One integer per line representing the maximum of the total value (this number will be less than 231).
Sample Input

1

5 10

1 2 3 4 5

5 4 3 2 1


Sample Output

14

代码:

#include<iostream>

using namespacestd;

#include<string.h>

intf[1001],c[1001],w[1001];

int main() 

{
	
	int t,n,v;
	
	cin>>t;
	
	while(t--)
		
	{
		
		inti,j;
		
		memset(f,0,sizeof(f));
		
		cin>>n>>v;
		
		for(i=1;i<=n;i++)
			
			cin>>w[i];
		
		for(j=1;j<=n;j++)
			
			cin>>c[j];
		
		for(i=1;i<=n;i++)//01关键所在
			
			for(j=v;j>=c[i];j--)
				
				if(f[j-c[i]]+w[i]>f[j]) f[j]=f[j-c[i]]+w[i];
				
				cout<<f[v]<<endl; 
				
	}
	
	return 0;
	
} 



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