hihocoder #1168 : 运输货物

这题挺考思维的。。。以出口为根,将树看成不同层,每次都是从下向上运输货物。。。。

#include <iostream>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <bitset>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <climits>
#include <cstdlib>
#include <math.h>
#include <time.h>
#define maxn 100005
#define maxm 200005
#define eps 1e-7
#define mod 1000000007
#define INF 0x3f3f3f3f
#define PI (acos(-1.0))
#define lowbit(x) (x&(-x))
#define mp make_pair
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid 
#define rson o<<1 | 1, mid+1, R
#define pii pair<int, int>
#pragma comment(linker, "/STACK:16777216")
typedef long long LL;
typedef unsigned long long ULL;
//typedef int LL;
using namespace std;
LL qpow(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base;base=base*base;b/=2;}return res;}
LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}
//head

struct Edge
{
	int v;
	Edge *next;
}*H[maxn], E[maxm], *edges;

LL dis[maxn];
int a[maxn];
int dist, n, s;

void init()
{
	edges = E;
	memset(H, 0, sizeof H);
}

void addedges(int u, int v)
{
	edges->v = v;
	edges->next = H[u];
	H[u] = edges++;
}

void dfs(int u, int fa, int dep)
{
	if(a[u]) dist = max(dist, dep);
	dis[dep] += a[u];
	for(Edge *e = H[u]; e; e = e->next) if(e->v != fa) dfs(e->v, u, dep+1);
}

void work(int _)
{
	int u, v;
	scanf("%d%d", &n, &s);
	for(int i = 1; i < n; i++) {
		scanf("%d%d", &u, &v);
		addedges(u, v);
		addedges(v, u);
	}
	for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
	dist = 0;
	LL ans = 0;
	for(Edge *e = H[s]; e; e = e->next) {
		int v = e->v;
		dist = 0;
		dfs(v, s, 0);
		LL t1 = 0, t2 = 0;
		for(int i = 0; i <= dist; i++) {
			t1 += dis[i];
			if(dis[i] == 0 && t1 + t2 <= i) t2++;
			dis[i] = 0;
		}
		ans = max(ans, t1 + t2);
	}
	printf("Case #%d: %lld\n", _, ans);
}

int main()
{
	int _;
	scanf("%d", &_);
	for(int i = 1; i <= _; i++) {
		init();
		work(i);
	}
	
	return 0;
}


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