UVA - 10099 The Tourist Guide

题意:跟之前的一题Floyd是一样的,就是求路径中的最小值最大,然后求来回的次数,记住导游也要考虑进去
#include <iostream>
#include <cstdio>
#include <cstring>
#include  <algorithm>
using namespace std;
const int MAXN = 110;

int dp[MAXN][MAXN];
int n,r,a,b,t;

int main(){
    int cas = 1;
    while (scanf("%d%d",&n,&r) != EOF && n+r){
        memset(dp,-1,sizeof(dp));
        for (int i = 1; i <= n; i++)
            dp[i][i] = 0;
        while (r--){
            scanf("%d%d%d",&a,&b,&t);
            dp[a][b] = dp[b][a] = t;
        }
        for (int k = 1; k <= n; k++)
            for (int i = 1; i <= n; i++)
                for (int j = 1; j <= n; j++)
                    dp[i][j] = max(dp[i][j],min(dp[i][k],dp[k][j]));
        scanf("%d%d%d",&a,&b,&t);
        int ans = dp[a][b] -1;
        printf("Scenario #%d\n",cas++); 
        printf("Minimum Number of Trips = %d\n\n",t/ans+(t%ans?1:0));
    }    
    return 0;
}



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