【题目链接】
求出最小生成树的最大边权,扫一遍,统计答案。
/* Pigonometry */ #include <cstdio> #include <utility> #include <algorithm> using namespace std; typedef pair<int, int> pii; const int maxn = 1005, maxm = 505, maxg = 500005, inf = 0x3f3f3f3f; int n, m, num[maxm], fa[maxn]; pii p[maxn]; struct _edge { int u, v, w; bool operator < (const _edge &x) const { return w < x.w; } } g[maxg]; inline int iread() { int f = 1, x = 0; char ch = getchar(); for(; ch < '0' || ch > '9'; ch = getchar()) f = ch == '-' ? -1 : 1; for(; ch >= '0' && ch <= '9'; ch = getchar()) x = x * 10 + ch - '0'; return f * x; } inline int find(int x) { return fa[x] == x ? x : fa[x] = find(fa[x]); } inline int sqr(int x) { return x * x; } inline int dis(pii a, pii b) { return sqr(a.first - b.first) + sqr(a.second - b.second); } inline int calc() { int tot = 0; for(int i = 1; i <= n; i++) for(int j = i + 1; j <= n; j++) g[++tot] = (_edge){i, j, dis(p[i], p[j])}; sort(g + 1, g + 1 + tot); int cnt = 0; for(int i = 1; i <= tot; i++) { int u = find(g[i].u), v = find(g[i].v); if(u != v) { ++cnt; fa[u] = v; if(cnt == n - 1) return g[i].w; } } return inf; } int main() { m = iread(); for(int i = 1; i <= m; i++) num[i] = iread(); n = iread(); for(int i = 1; i <= n; i++) fa[i] = i, p[i].first = iread(), p[i].second = iread(); int bot = calc(), ans = 0; for(int i = 1; i <= m; i++) if(num[i] * num[i] >= bot) ans++; printf("%d\n", ans); return 0; }