(Relax ST1.29)POJ 3749 破译密码(将一个字符串按照一定的规则转化成另外一个字符串)


/*
 * POJ_3749.cpp
 *
 *  Created on: 2013年11月26日
 *      Author: Administrator
 */

#include <iostream>
#include <cstdio>
#include <string>

using namespace std;

char m[500];//也可以用map来做..

int main() {
	m['A'] = 'V', m['B'] = 'W', m['C'] = 'X', m['D'] = 'Y', m['E'] = 'Z', m['F'] =
			'A', m['G'] = 'B', m['H'] = 'C', m['I'] = 'D', m['J'] = 'E', m['K'] =
			'F', m['L'] = 'G', m['M'] = 'H', m['N'] = 'I', m['O'] = 'J', m['P'] =
			'K', m['Q'] = 'L', m['R'] = 'M', m['S'] = 'N', m['T'] = 'O', m['U'] =
			'P', m['V'] = 'Q', m['W'] = 'R', m['X'] = 'S', m['Y'] = 'T', m['Z'] =
			'U';

	string str;
	string ans;
	while(getline(cin,str)){//***这是C++种的读取一行的写法...
		if(str == "START"){
			continue;
		}else if(str == "END"){
			cout << ans <<endl;
			ans.clear();
		}else if(str == "ENDOFINPUT"){
			break;
		}else{
			int len = str.length();

			int i;
			for(i = 0 ; i < len ; ++i){
				if(isalpha(str[i])){
//					ans += m[str[i]];
					ans.push_back(m[str[i]]);//建议用这种写法,上面的写法有警告...
				}else{
					ans += str[i];
				}
			}
		}
	}

	return 0;
}


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