递归字典排列

ttp://acm.xmu.edu.cn/JudgeOnline/problem.php?id=1005、

搞死我了。。。下面是找到的答案。。

Description

Generate the complete permutation of  1..N

Input

Each input file contains only one non-negative integer N (0< N < 9)

Output

Output N! Lines, according to lexicographic order.

Sample Input

3

Sample Output

1 2 3

1 3 2

2 1 3

2 3 1

3 1 2

3 2 1

#include

#include

#include

using namespace std;

int n;

int ans[10];

int used[10];

void perm(int k){

 int i,j;

 if(k==n){

  for(i=0;i<<ans[i]<<" ";

  cout<<ans[i]<<endl;

  return ;

 }

 for(i=0;i

  if(used[i]==0) {ans[k]=i+1;used[i]=1;}

  else {continue;}

    perm(k+1);

    ans[k]=0;

    used[i]=0;

 }

}

int main()

{

cin>>n;

perm(0);

return 0;

}

//自己还用链表，我晕 这时间和空间都大大的大

//把问题考虑复杂了 把数字借整数进行一个转换。。。。

#include

#include

#define MAXSIZE 9

struct list{

int val;

struct list *next;

};

struct list *create_next(struct list* head,int n);

void print_list(struct list*,int n);

void sort(struct list*);

int coef[MAXSIZE],a[MAXSIZE];

int totalNum=0;

int main()

{

int n=0;

scanf("%d",&n);

struct list *head_new = NULL;

int i=0;

coef[0]=1;

for(i=1;i

coef[i]=coef[i-1]*10;

}

for(i=1;i<=n;i++)

head_new=create_next(head_new,i);

sort(head_new);

print_list(head_new,n);

return 0;

}

struct list *create_next(struct list* head,int n)

{

struct list *p=head;

struct list *head_new=NULL;

struct list *p_new=NULL;

if(head==NULL){

head = (struct list*)malloc(sizeof(struct list));

head->val=1;

head->next=NULL;

return head;

}

totalNum=0;

for(;p!=NULL;p=p->next){

int temp=0;

int j=0;

for(j=0;j

if(j!=0)

a[j]=p->val-temp;

else

a[j]=p->val;

a[j]=a[j]/coef[n-2-j];

temp+=a[j]*coef[n-2-j];

}

for(j=0;j

int result=0;

int idx=0;

int k=0;

for(k=0;k

if(k==j){

result+=n*coef[n-1-k];

continue;

}

else{

result+=a[idx]*coef[n-1-k];

}

idx++;

}

struct list* temp_new = (struct list*)malloc(sizeof(struct list));

temp_new->val=result;

temp_new->next=NULL;

totalNum++;

if(head_new==NULL){

head_new = temp_new;

p_new = temp_new;

}

else{

p_new->next=temp_new;

p_new = p_new->next;

}

}

}

return head_new;

}

void print_list(struct list* head,int n)

{

for(;head!=NULL;head=head->next){

int temp=0;

int i=0;

for(i=0;i

int num = (head->val-temp)/coef[n-1-i];

temp += num*coef[n-1-i];

printf("%d ",num);

}

printf("\n");

}

}

void sort(struct list* head)

{

struct list* p= head;

int i,j;

for(i=totalNum-1;i>0;i--){

for(j=0;j

if(p->val>p->next->val){

int temp = p->next->val;

p->next->val = p->val;

p->val = temp;

}

p=p->next;

}

p=head;

}

}