c# winform 读取oracle中blob字段的图片并且显示到pictureBox里，保存进库

 private void button2_Click(object sender, EventArgs e)
 {
     OracleConnection conn = dbc.getConnection();//获得conn连接
     try
     {
         conn.Open();
         OracleCommand cmd = conn.CreateCommand();
         cmd.CommandText = "SELECT zp FROM kk.kkbj WHERE xh = 2345 ";//查询获得图片流

         OracleDataReader reader = cmd.ExecuteReader();//创建一个OracleDateReader对象
         reader.Read();

         MemoryStream ms = new MemoryStream((byte[])reader["zp"]);

         Image image = Image.FromStream(ms, true);

         reader.Close();
         conn.Close();

         pictureBox1.Image = image;
     }
     catch (Exception ee)
     {
         MessageBox.Show(ee.Message.ToString());
     }

 }

----------下边是上传和存入数据库有asp.net和winform(转)----------------------------------  

本文总结如何在.Net Winform和.Net webform(asp.net)中将图片存入sqlserver中并读取显示的方法 
    1，使用asp.net将图片上传并存入SqlServer中，然后从SqlServer中读取并显示出来 

    一，上传并存入SqlServer 

    数据库结构 
create table test 
{ 
     id identity(1,1), 
     FImage image 
} 

    相关的存储过程 
Create proc UpdateImage 
( 
     @UpdateImage Image 
) 
As 
Insert Into test(FImage) values(@UpdateImage) 
GO 

    在UpPhoto.aspx文件中添加如下: 

 <input id="UpPhoto" name="UpPhoto" runat="server" type="file">
 <asp:Button id="btnAdd" name="btnAdd" runat="server" Text="上传"></asp:Button>

    然后在后置代码文件UpPhoto.aspx.cs添加btnAdd按钮的单击事件处理代码: 

 private void btnAdd_Click(object sender, System.EventArgs e)
 {
         //获得图象并把图象转换为byte[]
         HttpPostedFile upPhoto=UpPhoto.PostedFile;
         int upPhotoLength=upPhoto.ContentLength;
         byte[] PhotoArray=new Byte[upPhotoLength];
         Stream PhotoStream=upPhoto.InputStream;
         PhotoStream.Read(PhotoArray,0,upPhotoLength);

         //连接数据库
         SqlConnection conn=new SqlConnection();
         conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

         SqlCommand cmd=new SqlCommand("UpdateImage",conn);
         cmd.CommandType=CommandType.StoredProcedure;

         cmd.Parameters.Add("@UpdateImage",SqlDbType.Image);
         cmd.Parameters["@UpdateImage"].Value=PhotoArray;

         //如果你希望不使用存储过程来添加图片把上面四句代码改为：
         //string strSql="Insert into test(FImage) values(@FImage)";
         //SqlCommand cmd=new SqlCommand(strSql,conn);
         //cmd.Parameters.Add("@FImage",SqlDbType.Image);
         //cmd.Parameters["@FImage"].Value=PhotoArray;

 conn.Open();
 cmd.ExecuteNonQuery();
 conn.Close();
 }

    二，从SqlServer中读取并显示出来 

    在需要显示图片的地方添加如下代码: 

 <asp:image id="imgPhoto" runat="server" ImageUrl="ShowPhoto.aspx"></asp:image>

    ShowPhoto.aspx主体代码： 

 private void Page_Load(object sender, System.EventArgs e)
 {
      if(!Page.IsPostBack)
      {
                 SqlConnection conn=new SqlConnection()
                 conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

                 string strSql="select * from test where id=2";//这里假设获取id为2的图片
                 SqlCommand cmd=new SqlCommand()
                 reader.Read();
                 Response.ContentType="application/octet-stream";
                 Response.BinaryWrite((Byte[])reader["FImage"]);
                 Response.End();
                 reader.Close();
      }
 }

    3，在winform中将图片存入sqlserver，并从sqlserver中读取并显示在picturebox中 

    1,存入sqlserver 

    数据库结构和使用的存储过过程，同上面的一样 

    1.1,在窗体中加一个OpenFileDialog控件，命名为ofdSelectPic 

    1.2,在窗体上添加一个打开文件按钮，添加如下单击事件代码： 
   

 Stream ms;
 byte[] picbyte;
 //ofdSelectPic.ShowDialog();
 if (ofdSelectPic.ShowDialog()==DialogResult.OK)
 {
    if ((ms=ofdSelectPic.OpenFile())!=null)
    {
     //MessageBox.Show("ok");
     picbyte=new byte[ms.Length];
     ms.Position=0;
     ms.Read(picbyte,0,Convert.ToInt32(ms.Length));
     //MessageBox.Show("读取完毕!");

     //连接数据库
     SqlConnection conn=new SqlConnection();
     conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

     SqlCommand cmd=new SqlCommand("UpdateImage",conn);
     cmd.CommandType=CommandType.StoredProcedure;

     cmd.Parameters.Add("@UpdateImage",SqlDbType.Image);
     cmd.Parameters["@UpdateImage"].Value=picbyte;

     conn.Open();
     cmd.ExecuteNonQuery();
     conn.Close();

     ms.Close();
     }
    }

    2,读取并显示在picturebox中 

    2.1 添加一个picturebox,名为ptbShow 

    2.2 添加一个按钮，添加如下响应事件： 
     

 SqlConnection conn=new SqlConnection();
 conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";

 string strSql="select FImage from test where id=1";

 SqlCommand cmd=new SqlCommand(strSql,conn);

 conn.Open();
 SqlDataReader reader=cmd.ExecuteReader();
         reader.Read();

 MemoryStream ms=new MemoryStream((byte[])reader["FImage"]);

 Image image=Image.FromStream(ms,true);

         reader.Close();
         conn.Close();

 ptbShow.Image=image;

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