HDOJ 5417 Victor and Machine 水

Victor and Machine

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)
Total Submission(s): 240    Accepted Submission(s): 134

Problem Description

Victor has a machine. When the machine starts up, it will pop out a ball immediately. After that, the machine will pop out a ball every  w  seconds. However, the machine has some flaws, every time after  x  seconds of process the machine has to turn off for  y  seconds for maintenance work. At the second the machine will be shut down, it may pop out a ball. And while it's off, the machine will pop out no ball before the machine restart.

Now, at the  0  second, the machine opens for the first time. Victor wants to know when the  n -th ball will be popped out. Could you tell him?

 

Input

The input contains several test cases, at most  100  cases.

Each line has four integers  x ,  y ,  w  and  n . Their meanings are shown above。

1≤x,y,w,n≤100 .

 

Output

For each test case, you should output a line contains a number indicates the time when the  n -th ball will be popped out.

 

Sample Input

   
   
   
   

    
    
    
    2 3 3 3
98 76 54 32
10 9 8 100
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    10
2664
939
   
   
   
   

 

Source

BestCoder Round #52 (div.2)

 

/* ***********************************************
Author        :CKboss
Created Time  :2015年08月22日 星期六 21时57分18秒
File Name     :HDOJ5417.cpp
************************************************ */

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <string>
#include <cmath>
#include <cstdlib>
#include <vector>
#include <queue>
#include <set>
#include <map>

using namespace std;

int x,y,w,n;

int main()
{
    //freopen("in.txt","r",stdin);
    //freopen("out.txt","w",stdout);

    while(cin>>x>>y>>w>>n)
    {
        int X=x;
        int time=0;
        for(int i=2;i<=n;i++)
        {
            if(time+w<=x)
            {
                time+=w;
            }
            else
            {
                time=x;
                time+=y;
                x=x+y+X;
            }
        }
        cout<<time<<endl;
    }
    
    return 0;
}