hdoj 1865 1sting

1sting

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3981    Accepted Submission(s): 1484

Problem Description

You will be given a string which only contains ‘1’; You can merge two adjacent ‘1’ to be ‘2’, or leave the ‘1’ there. Surly, you may get many different results. For example, given 1111 , you can get 1111, 121, 112,211,22. Now, your work is to find the total number of result you can get.

Input

The first line is a number n refers to the number of test cases. Then n lines follows, each line has a string made up of ‘1’ . The maximum length of the sequence is 200.

Output

The output contain n lines, each line output the number of result you can get .

Sample Input

   
   
   
   

    
    
    
    3
1
11
11111
   
   
   
   

Sample Output

   
   
   
   

    
    
    
    1
2
8
   
   
   
   

 

大数斐波那契：

 

#include<stdio.h>
#include<string.h>
#include<math.h>
#define MAX 2000+10
char str[210];
int dp[210][MAX];
int main()
{
    int t,n,i,j,l;
    memset(dp,0,sizeof(dp));
    dp[1][0]=1;dp[2][0]=2;
    for(i=3;i<=200;i++)
    {
        for(j=0;j<MAX;j++)
        {
            dp[i][j]+=dp[i-1][j]+dp[i-2][j];
            if(dp[i][j]>=10)
            {
                dp[i][j+1]+=1;
                dp[i][j]-=10;
            }
        }
    }
    scanf("%d",&t);
    while(t--)
    {
        scanf("%s",str);
        l=strlen(str);
        for(i=MAX-1;i>=0;i--)
        if(dp[l][i]!=0)
        break;
        for(;i>=0;i--)
        printf("%d",dp[l][i]);
        printf("\n");
    }
    return 0;
}