Java 生成Json与解析

在JAVA中构造和解析JSON我用的是org.json，附件为相应的org.json.jar.

下面是两个函数，一个是创建JSON，一个是从文本构造JSON并解析之。

创建json

 //construct json and output it
 public String jsonTest() throws JSONException{
     JSONObject json=new JSONObject();
     JSONArray jsonMembers = new JSONArray();
     JSONObject member1 = new JSONObject();
     member1.put("loginname", "zhangfan");
     member1.put("password", "userpass");
     member1.put("email","[email protected]");
     member1.put("sign_date", "2007-06-12");
     jsonMembers.put(member1);

     JSONObject member2 = new JSONObject();
     member2.put("loginname", "zf");
     member2.put("password", "userpass");
     member2.put("email","[email protected]");
     member2.put("sign_date", "2008-07-16");
     jsonMembers.put(member2);
     json.put("users", jsonMembers);

     return json.toString();
 }

 解析json 

 //construct json from String and resolve it.
 public String jsonTest2() throws JSONException{
     String jsonString="{\"users\":[{\"loginname\":\"zhangfan\",\"password\":\"userpass\",\"email\":\"[email protected]\"},{\"loginname\":\"zf\",\"password\":\"userpass\",\"email\":\"[email protected]\"}]}";
     JSONObject json= new JSONObject(jsonString);
     JSONArray jsonArray=json.getJSONArray("users");
     String loginNames="loginname list:";
     for(int i=0;i<jsonArray.length();i++){
         JSONObject user=(JSONObject) jsonArray.get(i);
         String userName=(String) user.get("loginname");
         if(i==jsonArray.length()-1){
             loginNames+=userName;
         }else{
             loginNames+=userName+",";
         }
     }
     return loginNames;
 }

 JAVA中处理JSON还是相当方便的。