BNU20834：Excessive Space Remover

How do you remove consecutive spaces in a simple editor like notepad in Microsoft Windows? One way is to repeatedly "replace all" two consecutive spaces with one space (we call it an action). In this problem, you're to simulate this process and report the number of such "replace all" actions.

For example, if you want to remove consecutive spaces in "A very big joke.", you need two actions:

"A very  big    joke." -> "A very big  joke." -> "A very big joke."

Input

The input contains multiple test cases, one in a separate line. Each line contains letters, digits, punctuations and spaces (possibly leading spaces, but no trailing spaces). There will be no TAB character in the input. The size of input does not exceed 1MB.

Output

For each line, print the number of actions that are required to remove all the consecutive spaces.

Sample Input

A very  big    joke.
         Goodbye!

Output for Sample Input

2
4

Explanation

If you can't see clearly, here is the sample input, after replacing spaces with underscores:

A*very**big****joke.
*********Goodbye!

Rujia Liu's Present 5: Developing Simplified Softwares
Special Thanks: Youzhi Bao

题意是给出的字符串有若干连续的空格，每次将每个连续空格中的空格两两合并，要多少步才能使得每个区间只有一个空格，我们先找出区间最长的空格数，由于奇数必须会有多于的一个，于是我们可以将奇数看做偶数处理

 

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

char str[1024*1024+5];//1M

int main()
{
    int len,i;
    int maxn,space,ans;
    while(gets(str))
    {
        len = strlen(str);
        maxn = 0;
        space = 0;
        for(i = 0;i<len;i++)
        {
            if(str[i] == ' ')
            space++;//连续空格
            else
            {
                if(maxn<space)//找出最长的连续空格
                maxn = space;
                space = 0;
            }
        }
        ans = 0;
        while(maxn!=1)
        {
            if(maxn%2)//奇数多出一个，可以将多出的也看成是两个空格合并的过程
            maxn++;
            maxn/=2;
            ans++;
        }
        printf("%d\n",ans);
    }

    return 0;
}