快速选择

《数据结构与算法分析——c语言描述》  第七章


算法真的很重要,选择问题是这本书一个循序渐进的例子。这次把复杂度强行降到O(N)。


#include<stdlib.h>  
#include<stdio.h>  

int RandInt(int i, int j) {
	int temp;
	temp = (int)(i + (1.0*rand() / RAND_MAX)*(j - i));
	return temp;
}

void getRandomInt(int *A, int n) {
	for (int i = 0; i < n; i++) {
		A[i] = i + 1;
	}

	for (int i = 1; i < n; i++) {
		//std::swap(A[i], A[RandInt(0, i)]);    
		int randAdrr = RandInt(0, i);
		int t = A[i];
		A[i] = A[randAdrr];
		A[randAdrr] = t;
	}
}

int a[99999999];


typedef int ElementType;

void insertionSort(int *a, int n) {
	int j, p;
	int temp;

	for (p = 1; p < n; p++) {
		temp = a[p];
		for (j = p; j > 0 && temp < a[j - 1]; j--)
			a[j] = a[j - 1];
		a[j] = temp;
	}
}

void swap_my(ElementType *a, ElementType *b) {
	ElementType temp;
	temp = *a;
	*a = *b;
	*b = temp;
}

ElementType median3(ElementType a[], int left, int right) {
	int center = (left + right) / 2;
	if (a[left] > a[center])
		swap_my(&a[left], &a[center]);
	if (a[left] > a[right])
		swap_my(&a[left], &a[right]);
	if (a[center] > a[right])
		swap_my(&a[center], &a[right]);
	swap_my(&a[center], &a[right - 1]);
	return a[right - 1];
}




#define CUTOFF (3)

void qSelect(ElementType a[], int k, int left, int right) {
	if (left + CUTOFF <= right) {
		int i, j;
		ElementType pivot;
		pivot = median3(a, left, right);
		i = left;
		j = right - 1;
		while (1) {
			while (a[++i] < pivot) {}
			while (a[--j] > pivot) {}
			if (i < j)
				swap_my(&a[i], &a[j]);
			else
				break;
		}
		swap_my(&a[i], &a[right - 1]);//把枢纽元换回来
		if (k < i+1)//k从1开始,i从0开始,小于枢纽元
			qSelect(a, k, left, i - 1);
		else if (k > i+1)
			qSelect(a, k, i + 1, right);
	}
	else {
		insertionSort(a + left, right - left + 1);//第k大的位于left和right之间,拍一下序
	}
}

#define N 99999999

int main() {


	getRandomInt(a, N);

	int k;
	scanf("%d", &k);
	
	qSelect(a,k,0, N-1);
	
	printf("%d", a[k-1]);
}


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